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Balance This Equation (Answer solved Biyatches)
Okay, Neither my instructor or the students, a small class mind you, cannot figure this equation out. It might not be able to be solved, but there might as well be one. Anyone want to give this a shot???
Equation:
Cu(s) + HNO3(aq) --> Cu(NO3)2(aq) + NO(g) + H2O(l)
Answer:
3Cu(s) + 8HNO3(aq) --> 3Cu(NO3)2(aq) + 2NO(g) + 4H2O(l)
* I don't know how to do subscripts here, but you get the point!
peace.
Steve
Copper + Nitric Acid = Coppor Nitrite + Nitric Oxide + Water
I think the formula for Nitric Acid is wrong, isn't it H2N03? I'm prolly wrong, i only got a C for A Level Chemistry 
and if your teacher can't work it out, then you're definately screwed 
I'd try it, but I'm so fucking sick of Chem after how bad it was last year, I just wanna forget about it (and I'm a lazy bam )
mdma: the formula for nitric acid that he had is correct, HNO3
I think it is H3NO2
Because Hydrogen has 2 postive ionen H2+ (spelled right) and those 2 go to NO3-..and the 3 goes to H2..
i remember thats how it worked..
so H3NO2
been sooo long since i had chmestry, kinda miss it
on it gimme a sec
is it acidic or basic solution?
nm acidic
can't you do some kind of trick where you add an OH and H2O to the formula to help balance it like this??
CU + 3HNO3 + H20 -------> CU(NO3)2 + NO + 2H20 + OH
although this is balanced...i don't think that's right (its been tooooo long hehehe), but don't you have to do something like that??
| quote: |
| Originally posted by Floorfiller can't you do some kind of trick where you add an OH and H2O to the formula to help balance it like this?? CU + 3HNO3 + H20 -------> CU(NO3)2 + NO + 2H20 + OH although this is balanced...i don't think that's right, but don't you have to do something like that?? |
| quote: |
| Originally posted by Floorfiller can't you do some kind of trick where you add an OH and H2O to the formula to help balance it like this?? CU + 3HNO3 + H20 -------> CU(NO3)2 + NO + 2H20 + OH although this is balanced...i don't think that's right (its been tooooo long hehehe), but don't you have to do something like that?? |
| quote: |
| Originally posted by Turbonium that's exactly what u do, assign oxidation numbers, etc. I got an answer, but it's screwy, and I get this stuff right 99% of the time. r u sure u typed the eqn in right? double check it, i'll recheck mine again |
I get the initial part correct, but restoring it to normal eqn yield incorrect result, weird...
3Cu + 8H(+) + 2NO3(-) ---> 3Cu(2+) + 2NO + 4H2O
full eqn (if I did it right, which according to this, I didn't):
3Cu + 2HNO3 + 6H(+) ---> 3Cu(NO3)2 + 2NO + 4H2O
THis is a stinker, and I don't know enough of chemistry to understand the oxidation method...
| quote: |
| Originally posted by Evan Almae THis is a stinker, and I don't know enough of chemistry to understand the oxidation method... |
| quote: |
| Originally posted by Floorfiller your teacher should...what level chemistry are you in?? |
| quote: |
| Originally posted by Evan Almae LOL, Intro! This is for extra credit too, just cause the teach can't finger it out! |
Here are the oxid. numbers, just to accompany you if ur looking up oxid. numbers in the text. They're easy, trust me.
In chronological order...
Cu
Cu : 0
HNO3
H : +1
N : +5
O : -2
Cu(NO3)2
CU : +2
N : +5
O : -2
NO
N : +2
O : -2
H2O
H : +1
O : -2
| quote: |
| Originally posted by Turbonium Here are the oxid. numbers, just to accompany you if ur looking up oxid. numbers in the text. They're easy, trust me. In chronological order... Cu Cu : 0 HNO3 H : +1 N : +5 O : -2 Cu(NO3)2 CU : +2 N : +5 O : -2 NO N : +2 O : -2 H2O H : +1 O : -2 |
| quote: |
| Originally posted by Floorfiller you seem to remember better than i do...what is the rule? i saw that you added H+ and H2O and no OH?? don't you add OH to balance out the oxygens or something? i don't know...its been a good 6 years since AP chem in sophomore year in highschool hehehe... |
| quote: |
| Originally posted by Turbonium You only add OH if it's a basic solution. It's acidic though (HNO3 is nitric acid). |
check my answer below
|
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v
well kewlness is probably right hehehe...this is what i got
CU + 3HNO3 + H ------> CU(NO3)2 + NO + 2H2O
mine looks simple so there ne ner ne ner hehehe...
| quote: |
| Originally posted by kewlness The correct answer 5Cu + 12HNO3 -> 5Cu(NO3)2 + 2NO + 6H2O How I did it: assign the unknown coefficients as unknowns x1,x2,x3,x4,x5 x1Cu + x2HNO3 -> x3Cu(NO3)2 + x4NO + x5H2O Now you know that x1 - x3 = 0 for Copper x2 - 2x5 = 0 for Hydrogen 3x2 - 6x3 - x4 -x5 = 0 for Oxygen x2 - 2x3 - x4 = 0 for Nitrogen Solving for the system of equations (i used linear algebra but you can use any method you want), I got the solutions: x1= 5/6 t x2 = 2t x3= 5/6 t x4= 1/3 t x5= t where t is a parameter Now you have to choose a value t so that x1,x2,x3,x4,x5 are integers (1,2,3,4,5,6, etc...) while still being in the lowest denominator... The number that fits this category is where t=6 so therefore x1 = 5, x2 = 12 x3 = 5 x4 = 2 x5 = 6 I win. Go get that bonus mark tommorow |
| quote: |
| Originally posted by Turbonium Sorry but your answer is incorrect. 36 oxygen on left, 38 on right. |
| quote: |
| Originally posted by Turbonium Sorry but your answer is incorrect. 36 oxygen on left, 38 on right. |
Nice try though! Thanks everyone for helping by the way! Didn't want to leave that unsaid, your help is much appreciated!
hmm.. let me re-do that.. i think i screwed up somewhere... go linear algebra
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