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-- An updated Monty Show paradox for all you COR brainiacs
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Posted by Boomer187 on Oct-23-2006 22:50:

hey I esplained this to my stats class.



the solution I gave em is, I dunno why it works but it does.


Posted by mezzir on Oct-23-2006 22:51:

quote:
Originally posted by Akridrot
If they were allowed to ask questions and guess, it wouldn't be much of a problem would it?

In all of the variations I've seen, it's simply "BACK AND FORTH WITH THEM SAYING NO UNTIL ONE SAYS YES"

Also prove that the person who says yes KNOWS the other person's number.

AND WE ARE TO ASSUME THE OTHER NUMBER WRITTEN ON THE BOARD IS JUST RANDOM?


Posted by Akridrot on Oct-23-2006 22:54:

quote:
Originally posted by mezzir
AND WE ARE TO ASSUME THE OTHER NUMBER WRITTEN ON THE BOARD IS JUST RANDOM?


Yes.

Example:
quote:

Alice's number: 6
Bob's number: 283
Xander's numbers: 289, X


Posted by mezzir on Oct-23-2006 22:55:

quote:
Originally posted by Akridrot
Yes.

Example:

FUCK I HAVE NO IDEA
GIMME SOME TIME, I DON'T WANNA KNOW YET


Posted by Akridrot on Oct-23-2006 22:56:

Another problem (much easier):
quote:

On the small island of Oculazura is a volcano as well as a tribe of 100 completely logical people. It is a well-known fact about the Oculazurans that they each have blue eyes or brown eyes. However, since there are no mirrors or reflective surfaces on the island, none of them knows the colour of their own eyes, even though they can see the colour of everybody else�s. In fact, according to their strict religion, any person who is able to determine the colour of their own eyes must sacrifice themselves to the gods by jumping into the volcano at midnight on the night of their discovery. One day, a visiting tourist addresses the entire tribe and announces to them that at least one of the islanders has blue eyes. What happens next?


Posted by Psy-T on Oct-23-2006 23:19:

quote:
Originally posted by Akridrot
Another problem (much easier):
quote:
On the small island of Oculazura is a volcano as well as a tribe of 100 completely logical people. It is a well-known fact about the Oculazurans that they each have blue eyes or brown eyes. However, since there are no mirrors or reflective surfaces on the island, none of them knows the colour of their own eyes, even though they can see the colour of everybody else�s. In fact, according to their strict religion, any person who is able to determine the colour of their own eyes must sacrifice themselves to the gods by jumping into the volcano at midnight on the night of their discovery. One day, a visiting tourist addresses the entire tribe and announces to them that at least one of the islanders has blue eyes. What happens next?


if there is only one tribe member with blue eyes, the entire tribe will jump down the volcano that night.
if there are 2 tribe members with blue eyes, the 98 brown-eyed tribe members will plunge down the volcano that night, followed by the two blue-eyed tribe members the next night.
0+n tribe members with blue eyes, 100-n tribe members plunge that night, the rest follow suit on the next day.


Posted by mezzir on Oct-23-2006 23:35:

quote:
Originally posted by Akridrot
Better problem:

K I'M GONNA NEED SOME HELP
GOT IT MOST OF THE WAY FIGURED OUT, I JUST CAN'T QUITE CONCEPTUALIZE THE LAST PART
I MEAN WITHOUT ANY QUESTIONS OR ANYTHING YOU CAN IMMEDIATELY NARROW IT DOWN TO TWO POSSIBILITIES
THE FIRST NUMBER MINUS YOUR PERSONAL NUMBER, OR THE SECOND MINUS YOURS
FROM THERE I FEEL LIKE YOU'D NEED TO BE IN KAHOOTS WITH THE OTHER PERSON TO ASSUME THAT WHEN YOU FIRST ARE ASKED IF YOU KNOW THE OTHER NUMBER, YOU'RE THINKING OF THE NUMBER 1
THEN 2, THEN 3 ETC
I JUST CAN'T QUITE PUT IT TOGETHERFUCKFUCKFUCKLOLOLOLAAAAAHHHHH!!!!1
K JUST LMK WHAT THE HELL THE ANSWER IS


Posted by Akridrot on Oct-23-2006 23:40:

quote:
Originally posted by mezzir
K I'M GONNA NEED SOME HELP
GOT IT MOST OF THE WAY FIGURED OUT, I JUST CAN'T QUITE CONCEPTUALIZE THE LAST PART
I MEAN WITHOUT ANY QUESTIONS OR ANYTHING YOU CAN IMMEDIATELY NARROW IT DOWN TO TWO POSSIBILITIES
THE FIRST NUMBER MINUS YOUR PERSONAL NUMBER, OR THE SECOND MINUS YOURS
FROM THERE I FEEL LIKE YOU'D NEED TO BE IN KAHOOTS WITH THE OTHER PERSON TO ASSUME THAT WHEN YOU FIRST ARE ASKED IF YOU KNOW THE OTHER NUMBER, YOU'RE THINKING OF THE NUMBER 1
THEN 2, THEN 3 ETC
I JUST CAN'T QUITE PUT IT TOGETHERFUCKFUCKFUCKLOLOLOLAAAAAHHHHH!!!!1
K JUST LMK WHAT THE HELL THE ANSWER IS


*Sigh* Can't solve it on your own, huh? *tsk*

This may come as a shock to you, but:
























I don't know the answer either.


Posted by mezzir on Oct-23-2006 23:42:

quote:
Originally posted by Akridrot
I SUCK COCKLOL!

YOU FUCKING BASTARD!!!!!


http://www.austms.org.au/Publ/Gazet...thellaneous.pdf
PWNPWNPWNPWNPWNPWNPWNPWN
GOD DAMNIT I WANNA KNOW THE ANSWER


Posted by Psy-T on Oct-23-2006 23:42:

quote:
Originally posted by Akridrot
I don't know the answer either.


that's cause that question is flawed.

the word "no" doesnt help them with any sort of information whatsoever.
maybe if they were limited in scope of the integers, there'd be a chance to solve it, but with infinity available.. no way in hell.

edit: lol, i just realized the integers that xander writes at the end do give a limit, i'll have to reconsider now, damnit


Posted by mezzir on Oct-23-2006 23:44:

quote:
Originally posted by Psy-T
that's cause that question is flawed.

the word "no" doesnt help them with any sort of information whatsoever.
maybe if they were limited in scope of the integers, there'd be a chance to solve it, but with infinity available.. no way in hell.

ITS NOT INFINITY
THEY'RE LIMITED TO INTEGERS BETWEEN 1 AND THE BIGGER OF THE 2 NUMBERS XANDER WRITES
SO IT COULD BE A HUGE SCOPE, BUT ITS FINITE


Posted by Psy-T on Oct-23-2006 23:45:

quote:
Originally posted by mezzir
ITS NOT INFINITY
THEY'RE LIMITED TO INTEGERS BETWEEN 1 AND THE BIGGER OF THE 2 NUMBERS XANDER WRITES
SO IT COULD BE A HUGE SCOPE, BUT ITS FINITE


stop yelling at me!


Posted by mezzir on Oct-23-2006 23:46:

quote:
Originally posted by Psy-T
stop yelling at me!

I'M BEING FESTIVE!


Posted by Akridrot on Oct-23-2006 23:48:

quote:
Originally posted by mezzir
YOU FUCKING BASTARD!!!!!


http://www.austms.org.au/Publ/Gazet...thellaneous.pdf
PWNPWNPWNPWNPWNPWNPWNPWN
GOD DAMNIT I WANNA KNOW THE ANSWER


That's the exact pdf too. Good job googling answers, freak.

Sorry about misleading y'all though.


Posted by Psy-T on Oct-23-2006 23:50:

i still contend there's something wrong with the question


Posted by ZeJayMan on Oct-23-2006 23:50:

Brothers and sisters have I none,
but this man's father's son is my father's son.


Posted by Akridrot on Oct-23-2006 23:53:

quote:
Originally posted by ZeJayMan
Brothers and sisters have I none,
but this man's father's son is my father's son.


You


Posted by Akridrot on Oct-23-2006 23:54:

How do you cut a cake into 8 pieces with 3 slices?

(I know the answer)


Posted by Psy-T on Oct-23-2006 23:54:

quote:
Originally posted by ZeJayMan
Brothers and sisters have I none,
but this man's father's son is my father's son.


you're just being convulted there, that man is obviously you


3 points for me in this therad so far, right?

edit, damn akridrot *mumbles*


Posted by Psy-T on Oct-23-2006 23:56:

quote:
Originally posted by Akridrot
How do you cut a cake into 8 pieces with 3 slices?

(I know the answer)


when cake=

/-\
|0|
\-/

first slice \

second slice /

then flip it to the side and ----


Posted by Akridrot on Oct-23-2006 23:59:

quote:
Originally posted by Psy-T
when cake=

/-\
|0|
\-/

first slice \

second slice /

then flip it to the side and ----


You think you're soooooooooooooooooooo clever. But you are right.

*I'm going to change words to make it ungoogleable*

I want to put 14 packets of Nutra-Sweet into 3 cups of tea. How would I put an odd number of Nutra-Sweets in each cup?


Posted by ZeJayMan on Oct-24-2006 00:02:

zero in the first one, 7 in the other two>?


Posted by pkcRAISTLIN on Oct-24-2006 00:03:

quote:
Originally posted by Psy-T
you're the one who thinks that past event affect the future event by increasing your choices' probability from 2/5 to 2/3; the elimination of two doors does not increase the probability of your initial choices in being right, however, it does inherently tell us that those two doors have a zero probability of holding the car, and hence the last door has a probability of 3/5 of holding the car.


im not understanding the logic youve used, with the 3/5 here. why arent the odds changed to each door being 1/3 chance? if you had five doors, and five contestants got to choose a door each, the chances of a correct guess will increase that corresponding amount, but no unopened door is ever going to have more of a chance than any other unopened door.

after the host has opened the two empty doors, the probabilities change to 1/3 for each door, given that your two initial selections could already have the car covered.


Posted by ZeJayMan on Oct-24-2006 00:04:

You're more likely to have the car if you don't change your choice. End OFzersss


Posted by Psy-T on Oct-24-2006 00:06:

quote:
Originally posted by Akridrot
You think you're soooooooooooooooooooo clever. But you are right.

*I'm going to change words to make it ungoogleable*

I want to put 14 packets of Nutra-Sweet into 3 cups of tea. How would I put an odd number of Nutra-Sweets in each cup?


put the 14 in the teapot before you pour?


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