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-- The Math Thread (4 N3rdS!!!)
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there is a funny disproval of a fundamental axiom of euclidian geometry.

in highschool, you learned: there can be only one straight line passing through two given points, right? take Earth, for example, and it's south and north pole. you can draw as many lines (meridians) through them as you wish...

quote:

Originally posted by ::TranceVanDyk:: anybody got anything to solve?

yes. regardless of what you'll think, this is purely logical and math-related problem:

two old friends from back in college days meet:
-so how are you? got any children
-three, actually
-how old are they?
-well, the sum of their ages is the number of windows in that building.
-hmmm... that's still isn't enough.
-the oldest son has black hair.
-now i know the answer. your children are.......

so how old were his children? (once again, this utilizes nothing but logic and very simple math)

way over my head.

he has none!! windows aren't IN buildings, they are ON buildings!!

quote:

Originally posted by ::TranceVanDyk:: way over my head. he has none!! windows aren't IN buildings, they are ON buildings!!

reminds me of work today.


My boss tells me to find the weight(lb) of a piece of zircar(insualtion) based on his dimensions. Easy... Volume*density of zircar = weight !!!


He had autodesk inventor that by typing in the density of zircar and selecting the piece it will determine the wiehgt. So he did and compared it my answer. It was different. How could the this fundamental formula fail me compared to the computer. Well it was right in front of us. He had two holes in his insualtion that I forgot subtract from the volume duhhh. Sometimes putting your hand to paper will not solve a problem. It will be right in front of you

x^3 - 4x^2 + x + 6 = 0

hmmm dag I took numerical methods to solve ish like this up the nth degree. My school notes are at work though. Lunch if I remeber I will post some ish

aww i thought this was the meth thread for nerds

quote:

Originally posted by Trancealot x^3 - 4x^2 + x + 6 = 0 hmmm dag I took numerical methods to solve ish like this up the nth degree. My school notes are at work though. Lunch if I remeber I will post some ish

therefore (derivative), 0=3x^2 - 8x +1

i think... it's been a while...

quote:

Originally posted by kadomony here's one: disprove the pythagorean theorem.

draw a triangle on the sphere and the sum of angles is > 180; inside a sphere < 180


as for the original problem, you can look at the derivatives no?

quote:

Originally posted by whiskers as for the original problem, you can look at the derivatives no?

the derivatives will tell you the critical points (and second derivatives - points of inflection), but not the roots.

whats the answer to the logic test??

another problem. somebody factor 6x^2 + x - 1

(3x-1)(2x+1)

Someone want to double check that?

quote:

Originally posted by ierxium (3x-1)(2x+1) Someone want to double check that?

Sorry bro, that's not it. The answer is a couple posts back...

quote:

Originally posted by stevieboy32808 Sorry bro, that's not it. The answer is a couple posts back...

I know. I was talking about the new problem. Post above mine.

quote:

Originally posted by ierxium (3x-1)(2x+1) Someone want to double check that?

THANK YOU!!

i was having a bit of brain lapse.

quote:

Originally posted by ::TranceVanDyk:: THANK YOU!! i was having a bit of brain lapse.

What's my prize?

quote:

Originally posted by ierxium (3x-1)(2x+1) Someone want to double check that?

What a nooben I am. yes you're right.

since this is the math nerd thread...




does anyone have any good suggestions for books on set theory? or related math topics...

dealin with imaginaries now, i know the answers, but im having a little fun.

find the zero's of x^3 + x^2 - 4x - 24

HINT: its long, so i'll give u this. (x-3) is a factor.

x^2(x+1)-4(x+6)

So the zeros are 0, -1, and -6. please verify this TranceVanDyk....

quote:

Originally posted by stevieboy32808 x^2(x+1)-4(x+6) So the zeros are 0, -1, and -6. please verify this TranceVanDyk....

nope, im headin out of work, ill give u the answer when i get home. til then try try again.

Ok, cool.

quote:

Originally posted by ierxium What's my prize?

my respect

quote:

x^2(x+1)-4(x+6) So the zeros are 0, -1, and -6. please verify this TranceVanDyk....

the answers are x = -2(+/-)2i, 3
-----------------

find the zero's of x^3 + x^2 - 4x - 24

three roots. u find out through descartes rule that there is 1 positive zero, and 2 imaginary ones. so u know there are going to be imaginaries.

the hint was, (x-3) was a factor of the equation above. knowing that, u divide the equation by (x-3). the zero which is 3 b/c (3-3=0) is divided by the equation to get...

x^2 + 4x + 8

u cant factor it. so you use the quadratic equation to find the zeros. your answer should then be -2(+/-)2i.

answers are then x = 3, -2(+/-)2i

if u checked your answers 0, -1, and -6, they would not have equaled 0 in the original equation.

damn...

i've forgotten everything in a space of 2 years ...

some basic theory books, just out of interest, would be good.

Y = Whoever can solve this has problems with the ladies

quote:

Originally posted by KandyKid_420 Y = Whoever can solve this has problems with the ladies

ladies like a man who intelligent

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