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quote:

Originally posted by igottaknow I know I'm late to the game, I haven't read tru the thread, nor have I ever heard of this riddle. I'd ask if it's true that there are two doors, one leading to heaven and the other leading to hell. You'll be able to tell which door is which based on who lies. It's pretty simple.

but u only get 1 question, so you either ask 1 brother, or the other, not both

and based on ur question, u just find out who the liar is, NOT which door will go to heaven

quote:

Originally posted by Resnick and based on ur question, u just find out who the liar is, NOT which door will go to heaven

Doesnt the hell dude who lies guard the hell door?

Here's a good riddle.

There are 2 men who work at a gas station. They have a game where they guess who pulled up to the pump on the wrong side of their take filler. They have cameras on each stall as to look at the rear of the car in the stall. They cannot see the filler for the tank, they only find out who is correct when the customer gets out and either moves to a different pump or tries to fill as is. Bob is right 99% of the time, yet Jim is right only about 13 percent of the time. How is Bob so good at this?

quote:

Originally posted by igottaknow Doesnt the hell dude who lies guard the hell door?

No, you dont know wich one is in front of wich door. It would be way too easy!

A deaf-and-dumb man went into a subway. He walked up to the cashier's booth and gave the cashier, whom he had never met before, a dollar. The subway tokens cost 40 cents each. The cashier gave the man two tokens. Not a word was said, nor any sign given. How did the cashier know that the man indeed wanted two tokens?

The guy is dumb, the cashier ripped his ass off and since the guy is a complete idiot - of course no words were said. He just walked off. LOL - right?

quote:

Originally posted by Falcon-X No, you dont know wich one is in front of wich door. It would be way too easy!

I googled the answer good riddle

quote:

Originally posted by xGirlx The guy is dumb, the cashier ripped his ass off and since the guy is a complete idiot - of course no words were said. He just walked off. LOL - right?

haha, no but thats a good guess. the guy being dumb really has nothing to do with the answer.

Uhm, can you tell us the answer please?

quote:

Originally posted by xGirlx Uhm, can you tell us the answer please?

he gave the attendant 4 quarters which meant that he purposely gave him a dollar which is enough to get 2 tokens. most people read the question and think that the dollar refers to a paper dollar. so anyways, if he only wanted one token he would have given him 2 quarters but he gave him 4 instead.

quote:

Originally posted by Resnick maybe *sits in corner and refuses to admit defeat

Don't worry Resnick, that solution will not work

The furthest the corner piece can extend is like this:

|\
| \<---------- Midpoint
| \
| \
-----

At a 45 degree angle. The midpoint is clearly .45 meters away from the corner, at a 45 deg angle, but the distance from the outer corner to your piece of land is sqrt(2)=1.414... meters. 1.414-.45 > .9, so it's impossible

Easy to fix though: .5n + n >= sqrt(2) will suffice for a piece. So n=2*sqrt(2)/3 is long enough... use .95 and your riddle works

*edit* that picture looks retarded, but you get it.

quote:

Originally posted by Floorfiller You are given 5 bags. There are 10 beads in each of the bags. In four of the bags, the beads each weigh 10 kilograms. In the remaining bag, each bead weighs only 9 kilograms. All the bags and beads look identical. You must find out which bag has the lighter beads. The problem is that all the bags look identical and all the beads look identical. You can use a scale, but it has to be a single-tray scale, not a two-tray balance scale. Also, you may use the scale only once. How can you find out which bag has the lighter beads? just pulled this off the web...looking at the solution its pretty fucking hard...

Got this at an MS interview for the first time, answered it in 30 seconds . For 1<=n<=5, take n beads from bag n. The sum should be 10*n(n-1)/2, but will be short by (10-9)*n = n kilograms.

In general, the only necessary condition is that the number of bags must not exceed the number of items in the bag.

For a slightly more difficult problem, try this month's ponder:

Ponder this

Part 1 took me a few hours, but it's fun and reasonably challenging

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