TranceAddict Forums (www.tranceaddict.com/forums)
- Humour / Funny Stuff / Cool Web Sites
-- Unbeatable game !?!
Pages (2): [1] 2 »
Unbeatable game !?!
The author of this game claims it can't be won , can you prove him wrong ? http://www.ebaumsworld.com/pearl.shtml
i see. actually, it IS possible to win such a game. it's just a typical example of something called nim. whether ure gonna win or lose a nim game depends on what moves u make. if u always make the right moves, u will win no matter what moves your opponent makes. so in this case we have a 3-4-5-6 structure of pearls, which means if u want tt win, u will have to start FIRST. all u need to do is to keep making the correct moves and u will win no matter what. next, if u took any math/computer logic courses that have something to do with algorithms, u would learn that applying binomial calcualtions would make it much easier for u to win/understand a nim.
in this case,
3 = 11
4 = 100
5 = 101
6 = 110
--------
1=1
2=10 u will need these during the game
okay, i'm not going to go into deep explanations as to why the following works (go take an algorithms course), i'll just give u the essentials. u need to find the initial set-up by adding binary numbers togerther as though u were using decimal numeration. in this case: 110+101+100+11 = 322. your goal is to always make moves that would yield a remaining number all digits of which are EVEN except for the last move, using the above system for your calculations. for example, u can easily make 222=110+101+11 out of 322 with one move. so u just need to get rid of 100 (4) to accomplish this. so just remove 4 pearls from any row. when i played, i removed the entire row 4. the guy then removed only 1 ball from row 5, amking the remaining number equal 110+101+1=212. so i wanted it to be 202. 202 -> 101+100+1 -> 5+4+1. i removed 2 pearls from row 6. he removed 1 pearl from row 6, making it 101+11+1=113 and so on...
summary of moves:
me 322 -> 222
he makes 212
me 212 -> 202
he makes 113
me 113 -> 22
he makes 13
last move, therefore u have to leave 3 (odd) and not 2
13-> 3 = 1+1+1
HE LOST:
Nope.........not working out there. 
my head hurts...
FUCKING AAAAAAAA
but hey !!! this is what the ****** does sometimes in the middle... he'll make it EVEN!!!!! instead of keeping it odd he makes it even...
not kidding... but when he kept it odd i raped him.... LOL thanks for the detailed algorithm!!!
i have a course in my third year on algorithms.... 
... :d
mwhahaha, took a few tries, but I beat him
i suck
well, it doesn't really matter if u go first or not...
i've won more times letting him go first than i going first
it's all dependent on your last 3 rows of pearls and their composition
that /&$%$%#$(=)=)=??())?$$%#$ son of a )(/%(%$&%//&#&%()()
if he laughs again i'm gonna kill him!!!!
i understood acidjunkies explanation but i don't know how to translate that into moves..
okay, here'are 4 possible scenarios that can happen to u if u start by removing the entire row of 4 balls.
ooo
xxxx
ooooo
oooooo (4 balls out after the first move)
scenario 1
me 322 -> 222 (6+5+3)
the guy 222 -> 221 (6+5+2)
me 221 -> 220 (6+4+2)
the guy 220 -> 121 (4+3+2)
me 121 -> 22 (3+2+1)
the guy 22 -> 13 (3+1+1)
me (last move) 13 -> 3 (1+1+1)
scenario 2
me 322 -> 222 (6+5+3)
the guy 222 -> 212 (6+5+1)
me 212 -> 202 (5+4+1)
the guy 202 -> 113 (5+3+1)
me 113 -> 22 (3+2+1)
the guy 22 -> 13 (3+1+1)
me (last move) 13 -> 3 (1+1+1)
scenario 3
me 322 -> 222 (6+5+3)
the guy 222 -> 221 (6+4+3)
me 221 -> 220 (6+4+2)
the guy 220 -> 121 (4+3+2)
me 121 -> 22 (3+2+1)
the guy 22 -> 13 (3+1+1)
me (last move) 13 -> 3 (1+1+1)
scenario 4
me 322 -> 222 (6+5+3)
the guy 222 -> 212 (5+4+3)
me 212 -> 202 (5+4+1)
the guy 202 -> 113 (5+3+1)
me 113 -> 22 (3+2+1)
the guy 22 -> 13 (3+1+1)
me (last move) 13 -> 3 (1+1+1)
acid junkie is a genius
*I bow*
I used that algorithm stuff and won!!!! yay!!!! but lost many times prior.
GENIUS, PURE GENIUS!
THANX ACID!
FINALLY OWNED THIS PAIN IN THE ASS DUDE!!
Finally I won this stupid game.........considering I didn't quite understand the help that was being givin.......thanks anyway though.
The algorithm doesn't seem to work if you dont take out the 4th row pearls on 1st move.
I tried it many different ways, and it wouldn't work besides taking out the 4th row first.
| quote: |
| Originally posted by Srezic The algorithm doesn't seem to work if you dont take out the 4th row pearls on 1st move. I tried it many different ways, and it wouldn't work besides taking out the 4th row first. |
aaaaaaah
fuck this game
fuck it to hell 
Thanks for the info Acid Junkie. I want to take some of those classes now 
Is that algorithm suppsoed to be full proof? Cause it aint for me... How you supposed to tell when your last move is? I have been in siutaiotn where its my turn and if i make the enxt move even i will lose and if i make the enxt move odd i will still lose.
| quote: |
| Originally posted by Lofu_X Is that algorithm suppsoed to be full proof? Cause it aint for me... How you supposed to tell when your last move is? I have been in siutaiotn where its my turn and if i make the enxt move even i will lose and if i make the enxt move odd i will still lose. |
Respect Acid Junkie,those algorithms worked a charm
| quote: |
| Originally posted by Acid Junkie u keep it even until all remaining rows have only one binary digit in each. then u make it odd and leave your opponent with the odd number of rows of 1 ball each (it doesn't matter how many rows left as long as their total number is odd: 3,5,7,9,11,13 etc.) |
classic game
haha peurf!
who's laughing now vieille merde !??!
now i wish i had taken those damn math courses
would not have served me anyway except for now hehe
| quote: |
| Originally posted by heroon haha peurf! who's laughing now vieille merde !??! now i wish i had taken those damn math courses would not have served me anyway except for now hehe |
Powered by: vBulletin
Copyright © 2000-2021, Jelsoft Enterprises Ltd.