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Posted by kaffeine4nrg on Oct-21-2003 23:18:

a question about RAID...

i have a motherboard that is able to boot from raid (0,1,0+1) and i was wondering how you would go about setting up the hard drives. i am still waiting for my case and power supply to come in until i can set it up and would like to get ahead of the game. what i am trying to ask is, can you set up raid 0 on both ide 3 and 4 as well as raid 1 on ide 3 and 4. or do you have to have both hard drives configured the same such as raid 1 on ide 3 and raid 0 on ide 4. i was just wondering cause i want to make my new pc as fast as i can short of going scsi. if it matters i have a soyo p4i875p dragon 2 platinum edition and an intel p4 2.8G both with hyper threading support.
this is my 1st pc i am building on my own to replace my current slow pc. i have tried to search the soyo site with no luck and other sites about raid. the soyo site from what i found all they talk about is how to jumper the hard drives. about the raid sites all i have found is what the different raid levels are and what the benefits and drawbacks are.
i hope that i am making sense.

Posted by Erk on Nov-08-2003 00:08:

if you have 2 disks you can either configure them as:

1)
a raid 0 array (very fast but not safe - one disk dies->all data lost) it works like it is splitting the data and send it simultaneously to both of the disk making it nearly twice as fast as a single disk. You will not lose any diskspace.

2)
a raid 1 (mirror) array (not faster than a single disk but twise as safe) the data is stored identically on both disks. If one dies you can restore it with the other disk. You can use half the disk space you have paid for.

3)
a raid 1+0 array. you will need 4 disks for this. You have a raid 0 array with mirroring. safe and fast but expensive. Half diskspace usage.

you can have several arrays othe same motherboard, you can have a raid 0 array on disk1 and disk2 on the same time as a raid 1 array on disk3 and disk4. You have to use the whole disk for the array, you cannot have just one partition in an array.

Sorry for my loosy english skills