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-- Want to let me read your mind

Posted by arj1o1 on Nov-10-2003 19:53:

Want to let me read your mind

http://digicc.com/fido/

Posted by DJ_NRG on Nov-10-2003 21:28:

GOD DAMN!! That's crazy. And I can't figure out the mathematical principle behind it at all!!!

Posted by Srezic on Nov-10-2003 21:40:

Obviously a formula. Just dunno what it is hehe.

Posted by electric_soul on Nov-10-2003 22:15:

hmm... instead of thinking a formula i'd do an iterative try-out...
you just gotta find out 1 digit anyway

which is pretty fast on computers

fun nonetheless!!

Posted by swantonbomb45 on Nov-11-2003 01:16:

well isnt that special

Posted by Noisician on Nov-11-2003 01:20:

pfftt... this is retarded. division properties of natual numbers, anyone?

1st. the subtraction of two natural numbers that are composed of the same digits but in different order ALWAYS yields a number that is aliquot to 9.

2nd. a natural number is divisible by 9 if and only if the sum of its digits is divisible by 9 (that is, it's a multiple of 9)

[for example, 10347428372867454356401527 is divisible by 9 because 1+0+3+4+7+4+2+8+3+7+2+8+6+7+4+5+4+3+5+6+4+0+1+5+2+7=108 is divisible by 9 as well]

so if, at the end, u have a 3-digit number, and u give away 2 digits, it doesn't take a whole genius to figure out what the third digit is

example`

6387 <-- random number

jumble up --> 8763

8763-6387=2376 <-- subtract

circle any digit --> 3 for example

we have 2376=abcd <-- a+b+c+d=9p

u give away 2,7 and 6 in any order (u circled out 3, remember?)

therefore --> 6+2+7+b=9p <=> 15+b=9p

now, p is a natural number, b is a digit, ie b < 10, therefore in order for (15+b)/9 to be a whole number, b HAS to be 3

Posted by J.L. on Nov-11-2003 04:20:

acid junkie... you amaze me...

waterloo??

Posted by Anno Domino on Nov-11-2003 19:23:

haha i cheated...

Posted by arj1o1 on Nov-11-2003 20:05:

quote:
Originally posted by Anno Domino
haha i cheated...

how?