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Posted by Krypton on Dec-20-2005 01:33:

The Math Thread (4 N3rdS!!!)

I thought i'de do this for the math geeks in here. i love math, and since im doing a friends internet course for him, i thought ide just rip a problem out and see u guys can do it. im up to the level of pre-calculus, not in the big leagues yet, but the average informed person can probably do these.
----------------------
i know the answer to this one, but can u find it?

Find all the real RATIONAL zero's in this equation. (In other words, find how many time "x" crosses the "x" axis on a graph.)(or find all the real solutions of "x" that makes the equation = to zero. youll get a PRIZE!!!

x^3 - 4x^2 + x + 6 = 0

----------------------
SOLVED : y = 2(+/-)square root of 14

y = y^2 -3y -10

i have no clue how to find y now, even after factoring it.

y = (y-5)(y+2)

original problem is.

(y+2)/y = 1/y-5

WHAT THE IS Y!!!!????


Posted by sensorium on Dec-20-2005 01:35:

set everything equal to zero.


Posted by Krypton on Dec-20-2005 01:37:

quote:
Originally posted by ierxium
set everything equal to zero.


tried that, doesnt work.

y = y^2-3y-10

y-y = (y^2-3y-10)-y

0 = y^2-4y-10

if i use the quadratic equation, i get very ugly numbers that i know arent right. i dont think i can use the zero property anyways.


Posted by sensorium on Dec-20-2005 01:38:

Re: Little homework help (Calculus)

quote:
Originally posted by ::TranceVanDyk::
ive been working this one problem, and have worked it all the way to this point.

y = y^2 -3y -10

i have no clue how to find y now, even after factoring it.

y = (y-5)(y+2)

original problem is.

(y+2)/y = 1/y-5

WHAT THE IS Y!!!!????

edit:: ACTUALLY ITS precalculus, not all the way to the big leagues yet


y^2 - 3y - 10 - y = 0
y^2 - 4y - 10 = 0
(y-5)(y+1) = 0



y=5 y=-1


Posted by stevieboy32808 on Dec-20-2005 01:40:

Re: Re: Little homework help (Calculus)

quote:
Originally posted by ierxium
y^2 - 3y - 10 - y = 0
y^2 - 4y - 10 = 0
(y-5)(y+1) = 0



y=5 y=-1

That's incorrect. If you use F.O.I.L. to check your answer you will get y^2 - 4y - 5.

Trance van Dyk just start from here:
y^2 - 4y - 10 = 0
and use the quadratic formula because that is impossible to factor using regular methods.


Posted by Krypton on Dec-20-2005 01:42:

Re: Re: Little homework help (Calculus)

quote:
Originally posted by ierxium
y^2 - 3y - 10 - y = 0
y^2 - 4y - 10 = 0
(y-5)(y+1) = 0



y=5 y=-1


lol, nope, u factored it wrong.

what u factored equals y^2-4y-5. c = 10, no 5. this is damn hard.


Posted by Ted Promo on Dec-20-2005 01:42:

set everything equal to davedresden


Posted by sensorium on Dec-20-2005 01:43:

Re: Re: Re: Little homework help (Calculus)

quote:
Originally posted by stevieboy32808
That's incorrect. If you use F.O.I.L. to check your answer you will get y^2 - 4y - 5.


hence the


Posted by UWM on Dec-20-2005 01:43:

wait this is in a calc class? wtf?


Posted by AnotherWay83 on Dec-20-2005 01:44:

yep, stevieboy is right do what he says


Posted by Krypton on Dec-20-2005 01:45:

Re: Re: Re: Little homework help (Calculus)

quote:
Originally posted by stevieboy32808
That's incorrect. If you use F.O.I.L. to check your answer you will get y^2 - 4y - 5.

Trance van Dyk just start from here:
y^2 - 4y - 10 = 0
and use the quadratic formula because that is impossible to factor using regular methods.


i guess my answer's going to be y = 2 (+-)square root of 14


Posted by sensorium on Dec-20-2005 01:46:

Re: Re: Re: Re: Re: Little homework help (Calculus)

quote:
Originally posted by Demoted
Oh, I thought that was your "I just got the answer right as I sat on my wet fart." face.


Could be.


Posted by stevieboy32808 on Dec-20-2005 01:46:

56 not 14


Posted by Basstard on Dec-20-2005 01:47:

doesnt have to factorize for it to be correct. the more you advance in mathematics the more you'll be dealing with irrational numbers and "ugly" numbers. but heck i love it all


Posted by Krypton on Dec-20-2005 01:47:

yes, precalc.


Posted by Krypton on Dec-20-2005 01:50:

quote:
Originally posted by stevieboy32808
56 not 14


using the quadratic equation, you do get a descriminate of 56, but simplifying that down, it turns into 2(square root of 14).


Posted by Ted Promo on Dec-20-2005 01:51:

I wonder how old this image is...


Posted by stevieboy32808 on Dec-20-2005 01:55:

Re: TranceVanDyk

You're absolutely correct.

y = 2 (+-)square root of 14

My bad.


Posted by Marc Summers on Dec-20-2005 02:02:

y = (y-5)(y+2)

...

Use FOIL


Posted by nchs09 on Dec-20-2005 02:10:

have u tried using ROLF?


Posted by Renzo on Dec-20-2005 02:33:

4 (+ or -) square root of 56....all divided by 2

Your answers are 5.7417 and -1.7417


Posted by Xenocreator_PG_ on Dec-20-2005 02:36:


Posted by sensorium on Dec-20-2005 02:39:


Posted by nchs09 on Dec-20-2005 02:41:

hahahah +1


Posted by eROs.au on Dec-20-2005 02:44:

BWHAHAHAHAHAHA

that pic is great


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