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woah.

*brains*

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Its a hack basically...

http://mathforum.org/dr.math/faq/faq.0.to.0.power.html

I like math sorta, too bad I suck at it.

quote:

This fact is based on the laws of indices: 1) (x^a)(x ^b) = x^(a+b) 2) (x^a) / (x ^b) = x^(a-b) 3) (x^a)^b = (x^b)^a = x^(ab) --------------------- Consider x^n / x^n where n is a non-zero integer. Using the second law of indices, x^n / x^n = x^(n-n) = x^0 However, we also know that anything divided by itself is equal to 1 (ignoring 0). Therefore x^n / x^n = 1 Putting these two answers together: 1 = x^n / x^n = x^(n-n) = x^0 Therefore x^0 = 1. [x=0 is a curious case and is undefined] Hope that clears things up

http://answers.yahoo.com/question/i...09133746AAuXWPt

quote:

Originally posted by Joss Weatherby Its a hack basically... http://mathforum.org/dr.math/faq/faq.0.to.0.power.html I like math sorta, too bad I suck at it.

I'm also in the 'I suck at math' group.

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anything to the zero power is 1

quote:

Originally posted by Zombie0729 anything to the zero power is 1

but zero to the power of anything is zero! stupid math.

3^0 = 1
2^0 = 1
1^0 = 1
0^0 = ?
0^1 = 0
0^2 = 0
0^3 = 0

quote:

Originally posted by Zombie0729 anything to the zero power is 1

That makes sense when the value you're putting to the power of 0 actually is a value. 0 has no value. So what you're saying is, I have zero apples and I take my zero apples and power the amount of apples I have by 0. Suddenly 1 appears out of thin air?

Sorry, I can't except that as a logical answer.

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quote:

Originally posted by idoru http://answers.yahoo.com/question/i...09133746AAuXWPt

Sorry, didn't see this right away, Idoru. So the value is undefined? Not 0? So my calculator is wrong?

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quote:

Originally posted by cmay119 lehman's terms

i dont think your problem is with math.

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quote:

Originally posted by pkcRAISTLIN i dont think your problem is with math.

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