ok im a bit rusty with my trig guys and i need help with this question. please only 3 stupid responses per 1 smart one.





A fire hose held near the ground shoots water at a speed of 6.8m/s. at what angle should the nozzle point in order that the water land 2.0 meters away.

(hint there are two angles).



so lets call the angle A
vo=6.8m/s and its components are 6.8sinA and 6.8cosA for y and x respectivley.


x= 2.0m
xo= 0m
yo=0m
y=?

so first i did this

using

x=xo+vot+0.5at*t

2= 6.8cos(A)t

so cos(A)=0.294/t

then i use the time height equation to find height at vo (which is half time.) then multiply it by 2 to get full time.

t=2vosin(A)/9.81

t=1.39sin(A)


so i have two equations put one in the other and use the trig identity

2sin(A)cos(A) = sin(2A)

i get sin(2A)= 0.848

therefore A = 29 degrees

which is wrong.

and there should be another angle i dont know how though.

Did you know without Trigonometry, there would be no engineering?

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Did you know that if my auntie had balls, she'd be my uncle?

quote:

Originally posted by Paradox Lost Did you know without Trigonometry, there would be no engineering?

yea

fuck off next post i hope is an attempt to solve this .

its easy guys

...still hoping someone will chime in about the importance of lamps.

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He traded sands for skins, skins for gold, gold for life. In the end, he traded life for sand. Afari, Tales

fuck its only the arabs posting.. im screwed.

I thought math was something we had going for us?

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He traded sands for skins, skins for gold, gold for life. In the end, he traded life for sand. Afari, Tales

apparently not

its up to mrjivebojingles now.. you arabs are useless tits

The problem assumes the water is coming out in a straight line, but in reality, the water is coming out parabolically, and so therefore, you should be looking towards a quadratic equation for the water. It's a trick question, don't be fooled.

quote:

Originally posted by Krypton The problem assumes the water is coming out in a straight line, but in reality, the water is coming out parabolically, and so therefore, you should be looking towards a quadratic equation for the water. It's a trick question, don't be fooled.

If you read his work, you would notice that he did do a quadratic.

Do you have the answer in the back of the book?

Here's a link for equations for accelerated motion. I'm too lazy to write it out, I kinda sucked at physics.

http://id.mind.net/~zona/mstm/physi...ratedMotion.htm

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