tax...so gimme some money!!

Why should there be another dollar?! Plug other numbers in, and you'll see that one would have nothing to do with the other.

P.S. Or just read Mathematician Plays the Stock Market; this is where the problem is from.

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Last edited by armandzadza on Aug-11-2004 at 04:10

Each person in the room ended up paying only $9 each but you can't set it up like 9 x 3 = 27.

From the original $30 that was paid, the manager gave back $5, so the whole room ended up being only $25 and the remaining $5 was broken up into $2 and $3. So breaking it down we get:

30

25 + 5

25 + 2 + 3


So from $25 the three guys got $3 back so $25 + $3 = 28

and adding the remaining $2 the bellhop got we have $28 + $2 = $30.

I dunno if that is right. Blah. I'm just bored here.

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The $27 they paid included the $2 to the bellhop, so if you add the $2 again you're creating two dollars out of thin air. If you can do that, then you'll be rich.

9x3=27 and the bellhop took 2.
2+27=29

so where is the other dollar?

pretty poorly done. the owner gave him $5 to give to them. the bellhop took 2, leaving 3 to give to the tools in the room. $1 didnt go missing, it was already divided inside the $25

so in actual fact it turns out that the guys already paid $8.33 and had $1 in their pocket, simple

They each paid 10
But were only supposed to pay 8.33
They each were due 1.67 as a refund
They only got back 1.00

So they all paid 9.33 each for the room
And that dirty bellhop stole 0.67 from each one

I don't know about you, but that warrants a good ass beating for the bellhop in my book.

quote:

Originally posted by Nautilus They each paid 10 But were only supposed to pay 8.33 They each were due 1.67 as a refund They only got back 1.00 So they all paid 9.33 each for the room And that dirty bellhop stole 0.67 from each one I don't know about you, but that warrants a good ass beating for the bellhop in my book.

exactly... that bellhop aint gonna be rich if he's stealing $2 from customers

dont know if this works but oh well

they paid 30 bucks and got 3 back, so they paid 27 total. the bellhop kept 2 and the manager kept 25.

does that work?

not sure if it does..i actually dont think it does but decided to see anyway
so i guess i'm really saying there is no dollar?

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quote:

Originally posted by PinkChicken dont know if this works but oh well they paid 30 bucks and got 3 back, so they paid 27 total. the bellhop kept 2 and the manager kept 25. does that work? not sure if it does..i actually dont think it does but decided to see anyway

Yes it works.

All $30 can be accounted for easily at any point in the series of transactions. It just starts to get complicated when you count the $2 twice.

em what if im already rich?











although im not, im p0or

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quote:

Originally posted by Halcyon+On+On OOKA-OOKA ME NACHOS ME PRESS KEYS ON COMPUTER GOOD

quote:

Originally posted by PVD & T[]C 9x3=27 and the bellhop took 2. 2+27=29

The flaw lies in the 2+27=29 part. It should have read as follows...

9x3=27 and the bellhop took 2.
27-2=25

The manager took 30 and refunded 5 (30-5=25), so both halves of the equation balance. The way that the story is worded (with the bellhop taking $2 from the money that was returned) often leads to the $2 transaction being misinterpreted in the equation.

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