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dukes
meh!



Registered: Nov 2003
Location: No mans land
yet another maths problem

ok anyone happen to know how to find the genral solution to a ordinary differential equations (ODE's)


like how would i go about finding the genral solution of the ODE

ds/dt = s + 1


what is the methods i would follow to solve problems of a similar nature?

Old Post Feb-19-2004 16:15  Scotland
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Omegasox
AI for MVP



Registered: Sep 2002
Location: Pennsylvania

We need a Homework forum. And a forum where you can post essays for others to use.

Old Post Feb-19-2004 16:51  United States
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Neo nEro
tranceaddict



Registered: Nov 2002
Location: US

You need an intigrating factor

ds/dt - s = 1

IF = -1

which is exp(int(-1,t))=exp(-t)

then multiply that to the whole equation


so

ds/dt*exp(-t) - s*exp(-t) = exp(-t)


now the left hand side is a derivative:

d(s*exp(-t))/dt= exp(-t)

so you intigrate both sides and then divide by the exp(-t)

which gives you:

s*exp(-t) = -exp(-t)+C

so s= -1+C/exp(-t)= -1+C*exp(t)


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Old Post Feb-19-2004 17:19  United States
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dukes
meh!



Registered: Nov 2003
Location: No mans land

quote:
Originally posted by Neo nEro
You need an intigrating factor

ds/dt - s = 1
IF = -1

which is exp(int(-1,t))=exp(-t)



how do you find a sutable integrating factor?

its not really the answer to the question im after as much as how to answer these questions.

Old Post Feb-19-2004 17:40  Scotland
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caddyshack
gsmile



Registered: Jul 2003
Location: Lansing

quote:
Originally posted by dukes
how do you find a sutable integrating factor?

its not really the answer to the question im after as much as how to answer these questions.


if its a first order liner equation then the integrating factor is the junk in front of the s term once the equation is in standard form

Old Post Feb-19-2004 17:50  United States
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dukes
meh!



Registered: Nov 2003
Location: No mans land

i think im gonna give up because im never gonna learn this in time to hand in my coursework.

i may beable to grasp how to do that question (i still am a little confused with it but the next one is a tad more complicated. as in i cant get it in the form

ds/dt + s = ??

and such.

arg should have been to uni more

Old Post Feb-19-2004 18:08  Scotland
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caddyshack
gsmile



Registered: Jul 2003
Location: Lansing

quote:
Originally posted by dukes
i think im gonna give up because im never gonna learn this in time to hand in my coursework.

i may beable to grasp how to do that question (i still am a little confused with it but the next one is a tad more complicated. as in i cant get it in the form

ds/dt + s = ??

and such.

arg should have been to uni more


you want it in the form 1*s' + f(t)*s = g(t)

e^int(f(t)) is your integrating factor

all this is in your book some place

Old Post Feb-20-2004 03:16  United States
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Resnick
Supreme tranceaddict



Registered: Feb 2003
Location: Toronto

laplace transform it...its by far the easiest way...and if u dont know what that is just look up the rules for it in some book...it will make ur life a billion times easier


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Old Post Feb-20-2004 03:28  Canada
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Noctone
Supreme tranceaddict



Registered: Mar 2002
Location: Lincoln, NE, USA

Separation of variables is the simplest way to solve this problem. Laplace transform would also be very easy, but just slightly more complex.


___________________
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"Journey to the End of the Night"

Old Post Feb-23-2004 00:13  United States
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Massive84
Old Relic



Registered: Jul 2003
Location: Sequence Realm

quote:
Originally posted by Neo nEro
You need an intigrating factor

ds/dt - s = 1

IF = -1

which is exp(int(-1,t))=exp(-t)

then multiply that to the whole equation


so

ds/dt*exp(-t) - s*exp(-t) = exp(-t)


now the left hand side is a derivative:

d(s*exp(-t))/dt= exp(-t)

so you intigrate both sides and then divide by the exp(-t)

which gives you:

s*exp(-t) = -exp(-t)+C

so s= -1+C/exp(-t)= -1+C*exp(t)


how do you use this in real life :S, always found that a more intresting question than the equation it self @ school.

Old Post Feb-23-2004 00:26  Netherlands
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caddyshack
gsmile



Registered: Jul 2003
Location: Lansing

quote:
Originally posted by Noctone
Separation of variables is the simplest way to solve this problem. Laplace transform would also be very easy, but just slightly more complex.


can't seperate variables

Old Post Feb-23-2004 00:48  United States
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caddyshack
gsmile



Registered: Jul 2003
Location: Lansing

quote:
Originally posted by Massive84
how do you use this in real life :S, always found that a more intresting question than the equation it self @ school.


well this equation could describe the motion of a car in response to pushing the gas or maybe the current through a circuit. making it possible for you to have the freedom of a car and listen to music respectively

Old Post Feb-23-2004 00:52  United States
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