I know the right answer, because I looked in the back of the book, but I just can't work the problem out. I'm not asking anyone to do my homework because I'll just ask the teacher to do it but here, see if any of you can do it...
Boeing 747s seat 400 passengers and are priced at $200 million each, Boeing 777s seat 300 passengers and are priced at $160 million, and the European Airbus A330's seat 300 passengers and are priced at $120 million. You are the purchasing manager of an airline company and have a spending goal of $2400 million for the purchase of new aircraft to seat a total of 5000 passengers. Your company has a policy of supporting US industries, and you have been instructed to buy twice as many US manufactured aircraft (Boeing) as foreign aircraft (Airbus). Given the selection of three aircraft, how many of each should you order?
I don't know if I'v written the system of equations wrong. I'm using the Row Reduction Method of Matrices and I know for a fact I'm doing the operation correctly, so it must be my system of equations. I'v worked and reworked this problem for about an hour, and I'v just given up...
I checked what you got[5,5,5] That makes sense because
747:QTY 5 + 777:QTY 5 = 10 which is double of the A330:QTY 5
Only question I have is why did you do it 1x+1y-2z = 0
I see the problem as 2x+2y+z=0 because of the doubling with respect to the european plane? The answer is already there but I just want to know the reasoning for that.
___________________
ATB -Let u go
Iio - Rapture(riva edit)
Dj Encore - I see right through you
Lasgo - something
The best vocal tunes on LI RIP(2001-2002)
Feb-20-2009 04:13
Sunsnail
Global Moderator
Registered: Sep 2004
Location:
Re: Re: Smart people do this math problem
quote:
Originally posted by Trancealot
Only question I have is why did you do it 1x+1y-2z = 0
I see the problem as 2x+2y+z=0 because of the doubling with respect to the european plane? The answer is already there but I just want to know the reasoning for that.
That threw me off for a bit too, but I'm pretty sure its right.
Feb-20-2009 04:47
Krypton
83.798 g/6.022x10^23
Registered: Nov 2003
Location: Texas
Re: Re: Smart people do this math problem
quote:
Originally posted by Trancealot
Good ol linear programming. Simplex method!!!!
I checked what you got[5,5,5] That makes sense because
747:QTY 5 + 777:QTY 5 = 10 which is double of the A330:QTY 5
Only question I have is why did you do it 1x+1y-2z = 0
I see the problem as 2x+2y+z=0 because of the doubling with respect to the european plane? The answer is already there but I just want to know the reasoning for that.
2(5) + 2(5) + 5 = 25
Maybe you meant...
2(5) + 2(5) - 5 but it still equals 15 which is not zero. That is an invalid equation. Whereas...
5 + 5 - 2(5) = 0 is true. So I think it must be x + y - 2z = 0 but I still can't find the answer (5, 5, 5) doing the operation. My head is about to explode...The next question is a hybrid of this question, and so I can't do either one!
___________________
Feb-20-2009 05:01
winston
ultraviolet catastrophe
Registered: Nov 2005
Location: Yggdrasill
KRYPTON, THE SYSTEM DOES NOT WANT YOU TO SUCCEED. THEY ARE WEEDING YOU OUT, YOU ARE FIGHTING AGAINST YOUR NATURE, YOU WERE MEANT TO BE A CLERK, I KNOW YOU DON'T WANT TO ADMIT THAT SO YOU'LL WORK YOUR ASS OFF TRYING TO PROVE YOURSELF THAT YOU CAN 'GO THE MILE'
I'LL TELL YOU WHAT, WHY DON'T YOU SHOVE A BIT OF HOPE AND CHANGE UP YOUR ASS, GRAB YOUR LAME ASS GLOWSTICKS AND GO DANCE WITH YOUR REDNECK MOM. YOU REDNECK ASSHOLE, I HOPE YOU FAIL MISERABLY
Feb-20-2009 05:17
Krypton
83.798 g/6.022x10^23
Registered: Nov 2003
Location: Texas
quote:
Originally posted by winston
KRYPTON, THE SYSTEM DOES NOT WANT YOU TO SUCCEED. THEY ARE WEEDING YOU OUT, YOU ARE FIGHTING AGAINST YOUR NATURE, YOU WERE MEANT TO BE A CLERK, I KNOW YOU DON'T WANT TO ADMIT THAT SO YOU'LL WORK YOUR ASS OFF TRYING TO PROVE YOURSELF THAT YOU CAN 'GO THE MILE'
I'LL TELL YOU WHAT, WHY DON'T YOU SHOVE A BIT OF HOPE AND CHANGE UP YOUR ASS, GRAB YOUR LAME ASS GLOWSTICKS AND GO DANCE WITH YOUR REDNECK MOM. YOU REDNECK ASSHOLE, I HOPE YOU FAIL MISERABLY
AFGA F AEUFIA UIFH A FHAEIUR AIUOE AWIOHF EF AHWOIEFH AWIOHWIF EWI FWAHFWIAOFH OIEWFH IOWAFEI FHIEWAIEO OIWAEHFOI WAHFOIWAHFIOW FHWAIOEF YOU TOO!
You now have the values for Y and Z priced in terms of X. ***We've eliminated the Y and Z variables entirely***, so you can rewrite your original equations using nothing but X. If you do this, you should be able to get a numeric value for X..and can then plug it back in and solve for Y and Z.
My brain just exploded.
Last edited by Capitalizt on Feb-20-2009 at 05:56
Feb-20-2009 05:25
tachobg
Junior tranceaddict
Registered: Jan 2006
Location: Cambridge, MA / NYC
If you need to show work, Gaußian elimination seems like the least annoying method -- it will work, the only annoying thing is that it's easy to make mistakes in arithmetic.
If you don't need to show work, then matlab is your friend
Feb-20-2009 05:28
Krypton
83.798 g/6.022x10^23
Registered: Nov 2003
Location: Texas
Re: Re: Smart people do this math problem
quote:
Originally posted by Capitalizt
substitution is the only way I know but it takes alot of work.. Just pick one equation and eliminate a variable.
Lets use the third one:
x + y - 2z = 0
so..
x + y = 2z
divide both sides by 2..
(x + y)/2 = z
There is your substitution. Replace z in the first two equations with (x + y)/2. Your answer will be in all x's and y's.
Let's take the first equation and substitute:
400x + 300y + 300[(x+y)/2] = 5000
= 400x + 300y + (300x)/2 + (300y)/2 = 5000
eliminate the fraction by multiplying everything by 2..
You now have the values for Y and Z priced in terms of X. ***We've eliminated the Y and Z variables entirely***, so you can rewrite your original equations using nothing but X. If you do this, you should be able to get a numeric value for X..and can then plug it back in and solve for Y and Z.
My brain just exploded.
Unfortunately, I'm not allowed to use substitution, so this would be pointless...
And, for everyone who suggested the Gaussian Method, that's the method I'm using, I just called Row Reduction Method. They'r the same thing. I'm doing the operation correctly but I am still getting off the wall answers like negatives.
