quote:

Originally posted by Falcon-X No, you dont know wich one is in front of wich door. It would be way too easy!

I googled the answer good riddle

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quote:

Originally posted by xGirlx The guy is dumb, the cashier ripped his ass off and since the guy is a complete idiot - of course no words were said. He just walked off. LOL - right?

haha, no but thats a good guess. the guy being dumb really has nothing to do with the answer.

Uhm, can you tell us the answer please?

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quote:

Originally posted by xGirlx Uhm, can you tell us the answer please?

he gave the attendant 4 quarters which meant that he purposely gave him a dollar which is enough to get 2 tokens. most people read the question and think that the dollar refers to a paper dollar. so anyways, if he only wanted one token he would have given him 2 quarters but he gave him 4 instead.

quote:

Originally posted by Resnick maybe *sits in corner and refuses to admit defeat

Don't worry Resnick, that solution will not work

The furthest the corner piece can extend is like this:

|\
| \<---------- Midpoint
| \
| \
-----

At a 45 degree angle. The midpoint is clearly .45 meters away from the corner, at a 45 deg angle, but the distance from the outer corner to your piece of land is sqrt(2)=1.414... meters. 1.414-.45 > .9, so it's impossible

Easy to fix though: .5n + n >= sqrt(2) will suffice for a piece. So n=2*sqrt(2)/3 is long enough... use .95 and your riddle works

*edit* that picture looks retarded, but you get it.

Last edited by Flyboy217 on May-21-2004 at 03:40

quote:

Originally posted by Floorfiller You are given 5 bags. There are 10 beads in each of the bags. In four of the bags, the beads each weigh 10 kilograms. In the remaining bag, each bead weighs only 9 kilograms. All the bags and beads look identical. You must find out which bag has the lighter beads. The problem is that all the bags look identical and all the beads look identical. You can use a scale, but it has to be a single-tray scale, not a two-tray balance scale. Also, you may use the scale only once. How can you find out which bag has the lighter beads? just pulled this off the web...looking at the solution its pretty fucking hard...

Got this at an MS interview for the first time, answered it in 30 seconds . For 1<=n<=5, take n beads from bag n. The sum should be 10*n(n-1)/2, but will be short by (10-9)*n = n kilograms.

In general, the only necessary condition is that the number of bags must not exceed the number of items in the bag.

Last edited by Flyboy217 on May-21-2004 at 03:42

For a slightly more difficult problem, try this month's ponder:

Ponder this

Part 1 took me a few hours, but it's fun and reasonably challenging