THANX ACID!

FINALLY OWNED THIS PAIN IN THE ASS DUDE!!

Finally I won this stupid game.........considering I didn't quite understand the help that was being givin.......thanks anyway though.

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The algorithm doesn't seem to work if you dont take out the 4th row pearls on 1st move.

I tried it many different ways, and it wouldn't work besides taking out the 4th row first.

quote:

Originally posted by Srezic The algorithm doesn't seem to work if you dont take out the 4th row pearls on 1st move. I tried it many different ways, and it wouldn't work besides taking out the 4th row first.

that's bs, dude. it only shows that u suck at math. the method i explained is only one of the many possible variations that could enable u to win. i didn't make this up; take any book that describes the basis of nim (or search on the internet even), i'm sure u'll find similar interpretations. the strategy for winning is the same for all nim games, and if u can't get it to work, well... u yourself are the problem here.


[edit]

in case u are too l33t to search for things, i did it for u. here's a good page. read and learn:

http://world.std.com/~reinhold/math/nim.html

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Last edited by Noisician on May-20-2003 at 02:31

aaaaaaah
fuck this game
fuck it to hell

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Thanks for the info Acid Junkie. I want to take some of those classes now

Is that algorithm suppsoed to be full proof? Cause it aint for me... How you supposed to tell when your last move is? I have been in siutaiotn where its my turn and if i make the enxt move even i will lose and if i make the enxt move odd i will still lose.

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TRANCE RULES.

quote:

Originally posted by Lofu_X Is that algorithm suppsoed to be full proof? Cause it aint for me... How you supposed to tell when your last move is? I have been in siutaiotn where its my turn and if i make the enxt move even i will lose and if i make the enxt move odd i will still lose.

u keep it even until all remaining rows have only one binary digit in each. then u make it odd and leave your opponent with the odd number of rows of 1 ball each (it doesn't matter how many rows left as long as their total number is odd: 3,5,7,9,11,13 etc.)

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Respect Acid Junkie,those algorithms worked a charm

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quote:

Originally posted by Acid Junkie u keep it even until all remaining rows have only one binary digit in each. then u make it odd and leave your opponent with the odd number of rows of 1 ball each (it doesn't matter how many rows left as long as their total number is odd: 3,5,7,9,11,13 etc.)

What do you mean by one binary digit each?

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TRANCE RULES.

classic game

haha peurf!

who's laughing now vieille merde !??!

now i wish i had taken those damn math courses

would not have served me anyway except for now hehe

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* architectural weapon designer