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zarathustra
0x40000000
Registered: Sep 2001
Location: Calgary
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Do not connect them in parallel, use a serial circuit. The reason for this is that the LEDs might have different operational voltage drops and they would each draw a slightly different amount of current resulting in slightly different brightnesses. In serial, they all have the same amount of current running through them.
The circuit should look like this:
+ ---[Switch]---[Resistor]-- +[LED1]- -- +[LED2]- -- +[LED3]- --
[9V]
- --------------------------------------------------------------
The order doesn't really matter, but make sure that the LEDs are in the right way (they have +ve and -ve ends) or they won't work. Typically, the longer lead is the +ve one.
The resistor is needed to ensure that the LEDs don't draw too much current. The best way to find out is if you have the LED data sheet. Find out what the operating current (I_L) and voltage (V_L) values are. Then do (V_s - 3*V_L) / I_L = R. Find a resistor that's close to (but greater than) R.
LEDs typically require V_L = 2 V and I_L = 20 mA. V_s = 9 V in this case so R = 150 Ohms.
Note: Blue LEDs require 4 V usually. You would need another 9 V battery if this is the case. Once again, this information would be in the data sheet.
PM me any questions, I would be glad to answer them.
Disclaimer: I am NOT responsible for any damage or personal injury caused by following these instructions.
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May-19-2005 18:42
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dave25285
tranceaddict in training
Registered: Jan 2004
Location: Blackpool UK
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You may already know, but as LED's are diodes the current can only flow one way through them so they need to be connected the right way round.
And as far as I can remember from my Electronics A-Level (a couple of years ago) the short leg is negative and the long one positive.
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May-19-2005 19:19
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