quote:

Originally posted by AnotherWay83 therefore -3 +e^x*e = 2+e^x/e^2 therefore e^x(1/e-1/e^2)=5; therefore e^x=5*(1/e-1/e^2) take the natural of both sides and u're dun

made another mistake here
here's the correction, sorry about that, i was trying to show off

therefore -3 +e^x*e = 2+e^x/e^2
therefore 5 = e^x(e-1/e^2)
therefore 5/(e-(e^-2)) = e^x
taking the natural log of both sides
x= Ln (5/(e-(e^-2)))

quote:

Originally posted by cbxzcm According to the book, the answer for 3^x = x^3 is 2.478 or 3.

x=3 is obvious, dont know how they got the 2.47...must be sum trix with natual logs

quote:

it means that either log(2x+5)=0 or log(9x^2)=0 ACtually when log(x)=0 it means that x = 1 so following that logic 2x+5 = 1 or 9x^2 = 1 x=-2 or x = +-1/3

Actually, log(9x^2)=2*[log3+logx). And you cant have a log from a negative number (what exponent makes 10 to be negative?).

So the only answer left is -log3=logx --> log(3^-1)=log(x) --> log(1/3)=log(x) --> x=1/3

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quote:

Originally posted by Palivar

some funny shit palivar

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