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Re: Re: Re: Another Bust
| quote: | Originally posted by rabbitjoker
- 4L MeOH containing 0.620 kg (20 mol) Methylamine
- 0.600 kg (10 mol) Glacial Acetic Acid
- 1.6 kg MDP2P
- 0.100 kg 10% Pt/C
Produces about 1.755 kg of MDMA (1,755,000 mg). At 100 mg / tablet that is 17,550 tablets.
Assuming we can use straight ratios (2812.5:1):
- 11250L MeOH containing 1743.75 kg (34875 mol) Methylamine
- 1687.5 kg (28125 mol) Glacial Acetic Acid
- 4500 kg of MDP2P
- 281.25 kg of 10% Pt/C
Would produce 4935.9375 kg of MDMA (4,935,937,500 mg). At 100 mg / tablet that would be 49,359,375 tablets. |
What did you have in your basement again? 
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