Registered: Jun 2004
Location: San Antonio, US : TXTA #156
It sounds right to me. You can express that answer in cells per ml^-1 which will be 7.5x10^6 cells/ml^-1. But it seems like you are doing it the right way and you have the right answer.
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I've never been able to eat a whole baby.
Kill the women. Eat the children.
It's just one of those days where you want to bend over everyone you know and kiss their ass goodbye with a big sideways boot.
Registered: Jun 2004
Location: San Antonio, US : TXTA #156
quote:
Originally posted by KiNeTiC ENeRgY
Good deal. It's tough to get anywhere in science w/o a phd anymore, and the money is usually garbage to boot.
Yeah if you're retarded and don't realize that you have huge fucking claws and fangs and that if you work for yourself you will make at least 100,000/year to upwards of tens of millions once the heavy hitters come around trying to buy your company.
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I've never been able to eat a whole baby.
Kill the women. Eat the children.
It's just one of those days where you want to bend over everyone you know and kiss their ass goodbye with a big sideways boot.
Plate the single-cell ES cell suspension in 50 ml fresh EB medium at a density of 105 cells ml-1 onto 15-cm bacterial dishes.
There are more examples there as well...
Last edited by NeoPhono on Dec-05-2008 at 20:39
Dec-05-2008 20:33
Zild
Ten City
Registered: Jun 2004
Location: San Antonio, US : TXTA #156
yeah ml^-1 is units per mil just like s^-1 = hz
___________________
I've never been able to eat a whole baby.
Kill the women. Eat the children.
It's just one of those days where you want to bend over everyone you know and kiss their ass goodbye with a big sideways boot.
Im just gonna write down all the info i have:
Ok the basic experiment is to work out the viability of a cuture of S. cerevisiae
We have already calculated the total count as 7.5x10^7 (or 75,000,000)
Now i'm calculating the Viable count (number of living cells).
I have calculated the average number of colonies in a 10^-4 dilution and a 10^-5 dilution.
In the 10^-4 dilution there were 165 colonies in agar.
So per ml I work this out to be 1.65x10^6 (correct?)
In the 10^-5 dilution there were 10 colonies in agar.
So per ml I work this out to be 1.0x10^6 (correct??)
The average of these two figures is 1.325x10^6 (or 1,325,000)
Percentage viability of a culture = viable cells divided by total cells x 100%
So 1.325x10^6 over 7.5x10^7 x100 = 1.77%
This seems very low to me, and i think i've missed a zero out somewhere beacause 17.7% would be more believable.
Any ideas???
Thanks everyone for this, its just I need to get past this to complete the rest of the work.
Cheers
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Dec-07-2008 16:49
Jackson
Supreme tranceaddict
Registered: Nov 2002
Location: t'North England
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Dec-07-2008 19:53
we_R_DNA
Thermionic Trance Mission
Registered: Jan 2004
Location: Right, Here
Re: NEW - Any scientists/mathmaticians? Quick question
quote:
Originally posted by Jackson
I've got a serious mental block and cant work this out.
What does ml-1 equal? I am not too bad with scientific notation since we've just come onto it. But I can't work it out...would it be nanolitres? centilitres?