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Originally posted by Heinz hmm.. howa bout no. your correct. but it had to be in Kelvin, and i rounded to the significant figure of 3 because the problem is made up of sig fig's of 3. ----------------------- P1=---- P2=----- V1=31.4 mL V2=25.0 L T1=23.6C T2=unknown Using Charle's Law of Gas. Pressure must be constant. His formula is... V1/T1 = V2/T2 (make into fraction.cant do on the keyboard.V1 OVER T1) Formulate Equation to find V2 (volume) 31.4/23.6 = 25.0/T2 Cross-multiply 23.6(25.0) = 590 --------->> 590 = 31.4(T2) 590/31.4 = 18.8 = T2 = 18.8C Convert Celsius measurement of 18.8C to Kelvin 273 + 18.8 = 291.8 Round 291.8 ---->> 292 K Temperature in smaller tank is 292K or 18.8C

FATAL mistake: All temperature units has to be changed Kelvins before any cross mulitiplication or applying formulas.

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Originally posted by Evil_Gnome Psh, chemistry is a piece of shit.

screw you. im going to major on chemistry. i love this subject.

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Originally posted by colonelcrisp charles law is significantly flawed as pressure IS NOT CONSTANT. you can solve it using bernoulli's equation for fluid mechanics or the First law of thermodynamics for closed systems. the solution doesnt result in 18.2 degrees however. and is significantly more complicated. and since i am studing for my fluids exam... i really dont have the time to draw out a solution to that one good luck with that chem tho

Heinz stated pressure was constant in the question. pointless reply.
The question was a high school chemistry question too. No one teaches complicated thermodynamics in first year of chemistry.

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Originally posted by Iyrlk FATAL mistake: All temperature units has to be changed Kelvins before any cross mulitiplication or applying formulas.

oh yeah.... i should know that.

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Originally posted by Mako Meh, screw atmospheric chemistry...Where's the real stuff? Like organic Chemistry?

Here ya go. What is the structure of the compound presented in this 1H NMR? Its composition is C10 H14 O.

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Origionaly posted by Neophono: Here ya go. What is the structure of the compound presented in this 1H NMR? Its composition is C10 H14 O.

And thermodynamics was too advanced for this thread.... sheesh..... thats one of those spectrophotometric readouts isnt it???

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Originally posted by pkcRAISTLIN I have 3 hobbies: gaming, DJing & correcting maladjusted fools on the internet.

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Originally posted by pkcRAISTLIN Yeah, I’d like to know what horrible, scarring incident in your childhood turned you into such an ignorant, intellectual-hating philistine?

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Originally posted by colonelcrisp And thermodynamics was too advanced for this thread.... sheesh..... thats one of those spectrophotometric readouts isnt it???

Yeah, an NMR spectra.

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Originally posted by NeoPhono Yeah, an NMR spectra.

Looks like an FFT at the output of an FM radio transmitter.

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Originally posted by DigiNut Looks like an FFT at the output of an FM radio transmitter.

Fast Fourier transforms? We don't need no stinkin' fast Fourier transforms!!! (From my comp engineering days)

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Originally posted by NeoPhono Here ya go. What is the structure of the compound presented in this 1H NMR? Its composition is C10 H14 O.

Looks like 4-isopropylanisole to me.

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Originally posted by starglider Looks like 4-isopropylanisole to me.

You are correct, although I believe anisole is a common name and not technically the "correct" way to name methyoxybenzene. So technicially (IUPAC speaking) it's 4-isopropyl-1-methoxybenzene, but I'd probably give you full credit, since anisole is methoxybenzene.