Here's a Taylor series I had to derive for my last problem set:

P = (RT/V1) [([2]V1+ ..

Blah fuck it it's way too long to write out.

If you really need help with something as straight forward as that then perhaps you've chosen the wrong subject to study.

cant help but here's something to make you laugh



edit: whats the world coming to when you cant even steal a crummy b/w mspaint gif?

Last edited by igottaknow on Sep-15-2005 at 18:06

quote:

Originally posted by igottaknow cant help but here's something to make you laugh

try hosting the pic yourself...its pretty funny though.

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quote:

Originally posted by lucid pro tip: if you value your life, NEVER do anything that will place you "outside" of the jonze circle of trust.

quote:

Originally posted by DJ Mikey Mike If you really need help with something as straight forward as that then perhaps you've chosen the wrong subject to study.

OY! your like 4 years older than me
just say how u do it dont be all pessimistic

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ok if i coun good the resul should be 3/5

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crowdfunding for my new album on vinyl

just use the cauchy's theorem
derive upper and down parts separately, eventually you'll have a real limit

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quote:

Originally posted by Mane ok if i coun good the resul should be 3/5

Yeah I got the same, its a few years since I did my calculus course however :P

Use L'Hopital's rule if you know what that is heh

3x/(2x^2+5x) = 3x/2x^2 + 3x/5x = 3/x + 3/5

lim x-->0 (3/2x + 3/5)


Ding.

Your shitty stick figure comics always crack me up.