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Balance This Equation (Answer solved Biyatches) (pg. 2)
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| Floorfiller |
| quote: | Originally posted by Evan Almae
THis is a stinker, and I don't know enough of chemistry to understand the oxidation method... |
your teacher should...what level chemistry are you in?? |
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| Evan Almae |
| quote: | Originally posted by Floorfiller
your teacher should...what level chemistry are you in?? |
LOL, Intro! This is for extra credit too, just cause the teach can't finger it out! |
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| Floorfiller |
| quote: | Originally posted by Evan Almae
LOL, Intro! This is for extra credit too, just cause the teach can't finger it out! |
well you'll be getting to this oxidation stuff...i'm sure its in your book. it looks like your teacher is just an and gave you guys an equation that he shouldn't have yet hehehe...:haha: |
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| Turbonium |
Here are the oxid. numbers, just to accompany you if ur looking up oxid. numbers in the text. They're easy, trust me.
In chronological order...
Cu
Cu : 0
HNO3
H : +1
N : +5
O : -2
Cu(NO3)2
CU : +2
N : +5
O : -2
NO
N : +2
O : -2
H2O
H : +1
O : -2 |
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| Floorfiller |
| quote: | Originally posted by Turbonium
Here are the oxid. numbers, just to accompany you if ur looking up oxid. numbers in the text. They're easy, trust me.
In chronological order...
Cu
Cu : 0
HNO3
H : +1
N : +5
O : -2
Cu(NO3)2
CU : +2
N : +5
O : -2
NO
N : +2
O : -2
H2O
H : +1
O : -2 |
you seem to remember better than i do...what is the rule? i saw that you added H+ and H2O and no OH?? don't you add OH to balance out the oxygens or something? i don't know...its been a good 6 years since AP chem in sophomore year in highschool hehehe... |
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| Turbonium |
| quote: | Originally posted by Floorfiller
you seem to remember better than i do...what is the rule? i saw that you added H+ and H2O and no OH?? don't you add OH to balance out the oxygens or something? i don't know...its been a good 6 years since AP chem in sophomore year in highschool hehehe... |
You only add OH if it's a basic solution. It's acidic though (HNO3 is nitric acid). |
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| Floorfiller |
| quote: | Originally posted by Turbonium
You only add OH if it's a basic solution. It's acidic though (HNO3 is nitric acid). |
thats right...good call...lemme try this again hehehe... |
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| kewlness |
check my answer below
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v |
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| Floorfiller |
well kewlness is probably right hehehe...this is what i got :conf: :conf:
CU + 3HNO3 + H ------> CU(NO3)2 + NO + 2H2O
mine looks simple so there ne ner ne ner hehehe... |
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| Turbonium |
| quote: | Originally posted by kewlness
The correct answer
5Cu + 12HNO3 -> 5Cu(NO3)2 + 2NO + 6H2O
How I did it:
assign the unknown coefficients as unknowns x1,x2,x3,x4,x5
x1Cu + x2HNO3 -> x3Cu(NO3)2 + x4NO + x5H2O
Now you know that
x1 - x3 = 0 for Copper
x2 - 2x5 = 0 for Hydrogen
3x2 - 6x3 - x4 -x5 = 0 for Oxygen
x2 - 2x3 - x4 = 0 for Nitrogen
Solving for the system of equations (i used linear algebra but you can use any method you want), I got the solutions:
x1= 5/6 t
x2 = 2t
x3= 5/6 t
x4= 1/3 t
x5= t
where t is a parameter
Now you have to choose a value t so that x1,x2,x3,x4,x5 are integers (1,2,3,4,5,6, etc...) while still being in the lowest denominator... The number that fits this category is where t=6
so therefore x1 = 5, x2 = 12 x3 = 5 x4 = 2 x5 = 6
I win. Go get that bonus mark tommorow |
Sorry but your answer is incorrect. 36 oxygen on left, 38 on right. |
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| Floorfiller |
| quote: | Originally posted by Turbonium
Sorry but your answer is incorrect. 36 oxygen on left, 38 on right. |
yeah that must mean that i win hehehehe :rolleyes: |
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| Evan Almae |
| quote: | Originally posted by Turbonium
Sorry but your answer is incorrect. 36 oxygen on left, 38 on right. |
I was just about to say that!:toothless Nice try though! Thanks everyone for helping by the way! Didn't want to leave that unsaid, your help is much appreciated!;) |
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