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Square root of the square root of -1
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| Zenchowdah |
also, sqrt(i)
try that one, ladies. |
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| reveal |
| sqrt(i) = 0.707106781 + 0.707106781 i |
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| Zenchowdah |
| quote: | Originally posted by reveal
sqrt(i) = 0.707106781 + 0.707106781 i |
gah! cheater. |
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| dj_mdma |
| quote: | Originally posted by reveal
sqrt(i) = 0.707106781 + 0.707106781 i |
0wn3d :p |
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| Mister_Michel |
Now my question is: What are you in life by knowing this? :conf:
(been asking myself that question for many years now, still no answer:nervous: ) |
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| Carl0s |
| quote: | Originally posted by reveal
sqrt(i) = 0.707106781 + 0.707106781 i |
| quote: | Originally posted by Zenchowdah
gah! cheater. |
congrats reveal. |
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| zayd |
| sqrt ( i ) = sqrt 2 + sqrt 2 i ? |
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| DigiNut |
| quote: | Originally posted by zayd
sqrt ( i ) = sqrt 2 + sqrt 2 i ? |
Actually, that's 1/sqrt(2), not sqrt(2).
It's easier if you figure it as i = e^i(90°). When you take the square root, halve the angle to get e^i(45°), then use the identity e^(ix) = cos x + i sin x. You could use this to find pretty much any real or complex power of i.
Anyway, complex numbers have very real meaning, you just don't learn it in high school. They're as fundamental to signal processing as arithmetic is to your high school courses. |
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| Scorchio |
| quote: | Originally posted by Mister_Michel
Now my question is: What are you in life by knowing this? :conf:
(been asking myself that question for many years now, still no answer:nervous: ) |
Your avatar is hot, got any pics of this girl? |
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| DigiNut |
| quote: | Originally posted by Scorchio
Your avatar is hot, got any pics of this girl? |
Yes, and while you're at it, why don't you start another ing "post pics of hot girls" thread dedicated to her! |
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| GeneDefekt |
| quote: | Originally posted by DigiNut
Yes, and while you're at it, why don't you start another ing "post pics of hot girls" thread dedicated to her! |
Actually you'd have to start another thread about "POST PICS OF HOT MEN" because that is actually a male's ass in his avatar. :eek: |
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