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calc
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| Turbonium |
What is the horizontal asymptote to this function?:
f(x) = ( 0.25 - x^2 ) / ( x^2 + x^4 )
The vertical asymptote is x = 0, but for the horizontal asymptote, I keep getting y = infinity.
wtf |
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| caddyshack |
| y=0 (x-axis), its the limit of the function, unless your function was an improper fraction, then you would need to divide |
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| Vigilante |
Do your own homework
:p |
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| TweeK |
| aaaaaah my head hurts:conf: |
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| Turbonium |
| quote: | Originally posted by caddyshack
y=0 (x-axis), its the limit of the function, unless your function was an improper fraction, then you would need to divide |
I keep getting y = infinity.
y = 0 IS correct, I have the answer sheet, but I don't get how u get it. Teacher says to divide all the terms by the highest one of the denominator (x^4), then sub in infinity for x to find the horizontal asymptote. Doesn't work ffs. |
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| Turbonium |
| nm I figured it out. I'm so ing "out of it" today, in terms of math, that I'm making stupid mistakes. |
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| icyhandofcrap |
f(x) = ( 0.25 - x^2 ) / ( x^2 + x^4 )
*
(1/x^4) / (1/x^4)
=
(.25 / x^4 - 1/x^2) / (1/x^2 + 1)
lim x-> infinity of that would be
(0 - 0) / (0 + 1)
=
0
dude... im in trig/anal H, and i know this |
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| icyhandofcrap |
| quote: | Originally posted by Turbonium
nm I figured it out. I'm so ing "out of it" today, in terms of math, that I'm making stupid mistakes. |
oh haha.. i get out of it sometimes too...
i bombed a trig test because umm apparently i "forgot" how to do simple algebra... im an idiot sometimes
but otherwise i am fine at math |
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| Turbonium |
How to factor this POS?:
0 = 2x^5 - x^3 - 0.5x |
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| eulerfx |
| First factor out the common x to make a tetric. Then set u = x^2 |
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