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Anyone good at math? (geometry)
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robin
Then PLEASE help me out here.. heh

I got a bunch of questions to do, if someone could help me out with the first couple i bet i can figure out the rest myself. I need to know how many cm^2's

here are 3



As for the first one, my guess would be 8:tan(55) which is 5.6. that could be right (then we'd have the hight) etc etc pytagoras. Overal answer 28cm^2

As for the 2nd one, i really don't know :(

If anyone would care to help me out here, please write down everything you do step by step.

Robin :(
Ken_Allen
:wtf:
robin
quote:
Originally posted by Ken_Allen
:wtf:


October 28th, 1990

Piss off ****, your not helping me with such a dumbass post.

Go play with your action man dolls or something..
ReAz
I will help you... I will edit in few minutes
Ken_Allen
quote:
Originally posted by robin
October 28th, 1990

Piss off ****, your not helping me with such a dumbass post.

Go play with your action man dolls or something..


Ever try looking at ur ing notes you stupidass? Or maybe you were just being a dumb and decided not to take any. And you can't do it if nothing was taught to you. :haha:
robin
Haha your pretty fun man :D

Nah seriously, its been four years or more since i did anything like this, those notes are looong gone.

:(
Ken_Allen
Heh...I learned it last year...but those notes are gone too :p

theres an easier way than with the tan crap
Boomer187
haha, this is really simple. I am gathering that you don't pay attentino in class or read your book.
Cloudburst
w8...it was the area... the law of cosines is good here.


A^2 = B^2 + C^2 - 2*BC*cos(a)

a is the angle and A is the side opposite the angle. B,C are the 2 other sides.

edit: area formula instead, look below.. :p
Dj Tomer
you can't use tan for the 1st triangle since its not a right-angle triangle. you have to use the sine and cosine formulas for all 3.

ReAz
in 3 the angles worth 77.5 each.

I cant find out how to do 1,2.sorry

edit: oh I got an idea wait 5 min...
Cloudburst
Heh, I forgot the Area formula... *slaps forehead*


Area = (B*C*sin(a)) / 2

look above for definition.
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