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Cool math tricks! (pg. 4)
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| THE_Chris |
| Being in 4th year of an Honours Physics Degree lets me tell you that yes, you all have a very long way to go yet :) It gets much, much harder. |
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| muckluck |
| Don't tell the three secrets of the number six! Number six and his bag of tricks. I'm in love with the number six, and the number six loves me. I had sex seven times with the number six in the shadow of a tree. Six has zero friends and one bastard child named nine. It's only twelve o'clock number six, don't run away this time! |
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| PersianMafia |
My math prof this year was telling our class that most mathematicians throughout the ages that have attempted to analyze infinity and infinit limits have all gone insane as a result of their attempts.
:wtf: |
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| ::TranceVanDyk:: |
| quote: | Originally posted by PersianMafia
My math prof this year was telling our class that most mathematicians throughout the ages that have attempted to analyze infinity and infinit limits have all gone insane as a result of their attempts.
:wtf: |
simply, we just cant comprehend infinite with our finite understanding. thus, what really is infinite? jesus called Himself, Alpha/Omega, beginning and end. God told moses, "I am that I am." could the christian god be the essence of infinite? or could it be brahman, or the cosmos? has the universe always been here? we just dont know...that is enough to drive a man insane. |
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| ::TranceVanDyk:: |
| quote: | Originally posted by Tranc3
Well certainly, the limit as N approaches infinity of the sum(i) from i=1 to n will equal infinity....if it's, say, a 9 behind a decimal, then yes the repeating number does indicate that it approaches 1. However, the only correct way to interpret your notation would be with significant figures....that is, you were measuring out a number to the nth significant place (and therefore simply truncating the remainder, changing the value of the sum, as it no longer approached infinity but rather a finite number).
The formal argument makes perfect sense and is absolutely correct logically, but you didn't follow the conditions necessary for the argument to support your conclusion. |
ok, all i know is that .99999 = 1 and i dont know how to explain it. so i got a source to do the explaining for me. u disagree, and im not as advanced in math as you, therefore i cant debate the subject with you. so i suggest u ask this dr. math guy and see what he says.
http://mathforum.org/dr.math/ask/
or simply ask your professor. |
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| Project 7 |
| What the is "math" |
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| Sunsnail |
| quote: | Originally posted by ::TranceVanDyk::
ok, all i know is that .99999 = 1 and i dont know how to explain it. so i got a source to do the explaining for me. u disagree, and im not as advanced in math as you, therefore i cant debate the subject with you. so i suggest u ask this dr. math guy and see what he says.
http://mathforum.org/dr.math/ask/
or simply ask your professor. |
well...
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.9 not .9999 |
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| ::TranceVanDyk:: |
| quote: | Originally posted by Sunsnail
well...
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.9 not .9999 |
same thing, just easier to type out. |
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| Dr. Cfire |
| quote: | Originally posted by Tranc3
Calc is based on Differentiation and Integration. The fundamental theorem of calculus involves taking the derivative of an integral, nothing more. Sure, their uses imply far more complex things, but calc is built off of those two principles. |
Sorry but its simplier than that
Fundamental Theorem of calculus:
if f is continuous on [a,b] and if F is any integeral of f on [a,b] then
b
S f(x)dx = F(b) - F(a)
a
note: plain text sucks, the S a b is a integral defined between b and a. |
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| Tranc3 |
| quote: | Originally posted by ::TranceVanDyk::
ok, all i know is that .99999 = 1 and i dont know how to explain it. so i got a source to do the explaining for me. u disagree, and im not as advanced in math as you, therefore i cant debate the subject with you. so i suggest u ask this dr. math guy and see what he says.
http://mathforum.org/dr.math/ask/
or simply ask your professor. |
No, I agree completely with the paper you pasted. I disagree with you. .9999 (with an arbitrary but finite number of nines) is not the same as .9999 (with an infinite number of nines) |
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| Tranc3 |
| quote: | Originally posted by Dr. Cfire
Sorry but its simplier than that
Fundamental Theorem of calculus:
if f is continuous on [a,b] and if F is any integeral of f on [a,b] then
b
S f(x)dx = F(b) - F(a)
a
note: plain text sucks, the S a b is a integral defined between b and a. |
Well really if you think about it, it's even simpler than that. Differentiation and integration are both based on and couldn't exist without limits. Even though the actual fundamental theorem of calculus states (http://en.wikipedia.org/wiki/Fundam...rem_of_calculus), I feel the truly fundamental theorem of calculus is the epislon-delta definition of the limit. But I'm not a mathematician, so I'm not the most qualified to say that kind of thing. |
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| Tranc3 |
| quote: | Originally posted by ::TranceVanDyk::
same thing, just easier to type out. |
One is impossible to type out, one is a finite value. Well both are actually finite values, in this case anyways, but the one that can be fully typed out without shorthand notation is not equal to 1. |
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