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Math geniuses... help with a simple equation (pg. 2)
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| Belgian Bonzai |
| quote: | Originally posted by Aquarian
dy = (6x + 5 - 2y)dx
y = 3x^2 + 5x - 2yx
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Hey dude, you obviously had integration calculus at school, thumbs up, but:
1: forgot integration constants
2: the indefinite integral of -2ydx is only -2yx+C if y is not a function of x.
:) |
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| Aquarian |
woops!
*disapears in a puff of logic* |
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| Joycey |
| quote: | Originally posted by Aquarian
woops!
*disapears in a puff of logic* |
Um is there really someone else out there who plays nethack? |
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| Joycey |
| quote: | Originally posted by Aquarian
what's nethack? |
Text based game. Just about the nerdiest game ive ever played.
*disapears in a puff of logic*... whats this a quote from? |
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| DJ Cinos |
| quote: | Originally posted by Joycey
Text based game. Just about the nerdiest game ive ever played.
*disapears in a puff of logic*... whats this a quote from? |
Hitchikers' guide to the galaxy. :D |
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| ::TranceVanDyk:: |
i got y = 2x + 5/3
i saw that first y to be y to the first power unless its something else. so on the side, when simplified, y + 2y = 3y = 6x + 5
the to get y, divided 3. (3y) / 3 = (6x + 5) / 3
to get y = 2x + 5/3 |
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| starglider |
| quote: | Originally posted by ::TranceVanDyk::
i got y = 2x + 5/3
i saw that first y to be y to the first power unless its something else. so on the side, when simplified, y + 2y = 3y = 6x + 5
the to get y, divided 3. (3y) / 3 = (6x + 5) / 3
to get y = 2x + 5/3 |
The notation y' means dy/dx. My recommendation is not to try to solve differential equations (even simple ones like this) unless you've learned how... they're often not intuitive. ;) |
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| ::TranceVanDyk:: |
| quote: | Originally posted by starglider
The notation y' means dy/dx. My recommendation is not to try to solve differential equations (even simple ones like this) unless you've learned how... they're often not intuitive. ;) |
i see...im going on algebra II experience...not much...:( |
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| Tranc3 |
| quote: | Originally posted by DJ Cinos
The previous poster wasn't correct? :conf:
The answer in this one seems rather complicated. |
Ok, are you in a class that uses or teaches calculus, or a class that doesn't use or teach calculus? This would explain whether the first variable is read as ("y prime" or "dy/dx" or "the derivative of y with respect to x" or whatnot) or ("y raised to the first power").
Actually, based off of your responses so far, you don't seem to know the difference. I'm going to assume you're in a non-calculus class, in which case the simple answer is the correct one. The other possibility I see (assuming my postulate is indeed correct) is that you've mistakenly enrolled in a calculus-based class, and are therefore ed. |
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| ChemEnhanced |
This question always got me in math
(2xy^4 + 34x^2y - x)^0 = Z |
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| DJ Cinos |
| quote: | Originally posted by Tranc3
Ok, are you in a class that uses or teaches calculus, or a class that doesn't use or teach calculus? This would explain whether the first variable is read as ("y prime" or "dy/dx" or "the derivative of y with respect to x" or whatnot) or ("y raised to the first power").
Actually, based off of your responses so far, you don't seem to know the difference. I'm going to assume you're in a non-calculus class, in which case the simple answer is the correct one. The other possibility I see (assuming my postulate is indeed correct) is that you've mistakenly enrolled in a calculus-based class, and are therefore ed. |
I think the simple answer will do for that. Y' means indeed it's the derivative of the whole Y.
What calculus means I sadly don't know. It's one of the few words missing from my english vocabulary.
But actually they might be looking for a more complex answer if such exists, all the other answers to similar stuff like
y'' + 8y = 4y' (which I managed to solve)
Have been more complicated. For that one it was
e^2x(C*cos2x + D*sin2x)
Stupid maths. :conf: |
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