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The Math Thread (4 N3rdS!!!)
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| ::TranceVanDyk:: |
I thought i'de do this for the math geeks in here. i love math, and since im doing a friends internet course for him, i thought ide just rip a problem out and see u guys can do it. im up to the level of pre-calculus, not in the big leagues yet, but the average informed person can probably do these.
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i know the answer to this one, but can u find it?
Find all the real RATIONAL zero's in this equation. (In other words, find how many time "x" crosses the "x" axis on a graph.)(or find all the real solutions of "x" that makes the equation = to zero. youll get a PRIZE!!!
x^3 - 4x^2 + x + 6 = 0
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SOLVED : y = 2(+/-)square root of 14
y = y^2 -3y -10
i have no clue how to find y now, even after factoring it.
y = (y-5)(y+2)
original problem is.
(y+2)/y = 1/y-5
WHAT THE :wtf::wtf::wtf::wtf: IS Y!!!!???? |
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| ierxium |
| set everything equal to zero. |
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| ::TranceVanDyk:: |
| quote: | Originally posted by ierxium
set everything equal to zero. |
tried that, doesnt work.
y = y^2-3y-10
y-y = (y^2-3y-10)-y
0 = y^2-4y-10
if i use the quadratic equation, i get very ugly numbers that i know arent right. i dont think i can use the zero property anyways. |
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| ierxium |
| quote: | Originally posted by ::TranceVanDyk::
ive been working this one problem, and have worked it all the way to this point.
y = y^2 -3y -10
i have no clue how to find y now, even after factoring it.
y = (y-5)(y+2)
original problem is.
(y+2)/y = 1/y-5
WHAT THE :wtf::wtf::wtf::wtf: IS Y!!!!????
edit:: ACTUALLY ITS precalculus, not all the way to the big leagues yet:p |
y^2 - 3y - 10 - y = 0
y^2 - 4y - 10 = 0
(y-5)(y+1) = 0
:wtf:
y=5 y=-1 |
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| stevieboy32808 |
| quote: | Originally posted by ierxium
y^2 - 3y - 10 - y = 0
y^2 - 4y - 10 = 0
(y-5)(y+1) = 0
:wtf:
y=5 y=-1 |
That's incorrect. If you use F.O.I.L. to check your answer you will get y^2 - 4y - 5.
Trance van Dyk just start from here:
y^2 - 4y - 10 = 0
and use the quadratic formula because that is impossible to factor using regular methods. |
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| ::TranceVanDyk:: |
| quote: | Originally posted by ierxium
y^2 - 3y - 10 - y = 0
y^2 - 4y - 10 = 0
(y-5)(y+1) = 0
:wtf:
y=5 y=-1 |
lol, nope, u factored it wrong.
what u factored equals y^2-4y-5. c = 10, no 5. this is damn hard. |
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| Demoted |
| set everything equal to davedresden |
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| ierxium |
| quote: | Originally posted by stevieboy32808
That's incorrect. If you use F.O.I.L. to check your answer you will get y^2 - 4y - 5.
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hence the :wtf: |
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| UWM |
| wait this is in a calc class? wtf? |
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| AnotherWay83 |
| yep, stevieboy is right do what he says |
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| ::TranceVanDyk:: |
| quote: | Originally posted by stevieboy32808
That's incorrect. If you use F.O.I.L. to check your answer you will get y^2 - 4y - 5.
Trance van Dyk just start from here:
y^2 - 4y - 10 = 0
and use the quadratic formula because that is impossible to factor using regular methods. |
i guess my answer's going to be y = 2 (+-)square root of 14 |
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| ierxium |
| quote: | Originally posted by Demoted
Oh, I thought that was your "I just got the answer right as I sat on my wet fart." face. |
Could be. |
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