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3^x - 2*3^(1-x) = 1 (pg. 2)
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| PaperBag831 |
| quote: | Originally posted by DJ Cinos
How does solve a beast such as this? I know it should be easy, but I just can't do it.
Any help appreciated. |
make the whole thing equal zero, so you just add a -1 to the equation. now put it in your calculator in the Y= part, and it'll form a graph. wherever that graph crosses that x-axis, thats your answer
:rolleyes: :rolleyes: :rolleyes: :rolleyes: |
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| DJ Cinos |
| quote: | Originally posted by sensorium
You might be the best note taker ever. |
No, but I don't take classes in English, smartass. They're called "Exponentiallagar" here, which directly translates to "Exponential Laws" |
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| DJ Cinos |
| quote: | Originally posted by PaperBag831
make the whole thing equal zero, so you just add a -1 to the equation. now put it in your calculator in the Y= part, and it'll form a graph. wherever that graph crosses that x-axis, thats your answer
:rolleyes: :rolleyes: :rolleyes: :rolleyes: |
The thing is, we can't use graph calculators. It'd be easy with one, yes... but we have to do it manually. |
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| Marc Summers |
| quote: | Originally posted by PaperBag831
MADD = mathematicians against drunk deriving.
dont drink and derive! |
omg... that joke was lame as cheese |
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| LeopoldStotch |
(3^x) - (2) * (3^(1-x)) = 1
3^x * 3^(1-x) = 3
"3" is a like base.
figure the rest.
:rolleyes:
[edit]
whoops. that's going to give you 0.
open a textbook. it's a lot better for you. |
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| DJ Cinos |
Are you sure it works like that? :p
(hint: no)
EDIT: Oh, you noticed it yourself. Ah well, there aren't any examples of this in my books either. I'd better just concentrate on the other stuff. :confused: |
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| PaperBag831 |
| quote: | Originally posted by Marc Summers
omg... that joke was lame as cheese |
its on a poster in the front of my math room |
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| PaperBag831 |
| turn 3^x into log |
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| Yan |
| I'm sure this will help you out somehow. |
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| DJ Cinos |
| quote: | Originally posted by Yan
I'm sure this will help you out somehow. |
It's not about derivatives.
However, I found an entry on Exponents too, which COULD be of use. |
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| piggy |
Divide both sides by 3^(1-x),
this gives you 3^(2x-1) - 2 = 3^(x-1).
Rearrange to get (1/3)*3^2x - (1/3)*3^x - 2 = 0
Let y = 3^x, then solve as a regular quadratic equation.
This gives you y = -2, 3
3 = 3^x , so x = 1. |
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| sensorium |
3^x - 6/3^x - 1 = 0
3^x - 2/1^x - 1 = 0 (1^x)
3^x^2 - 2 - 1^x = 0
3^x^2 - 1^x - 2 = 0
(3^x + 2)(1^x - 1) = 0
3^x = -2 1^x = 1
I forgot. |
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