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logarithms
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| Nrg2Nfinit |
how do i solve a negative logarithm
so i understand that when you use log (#)=n in your calculator its automatically solving for 10^n = #
so lets say i dont know "#". and its -log how do i solve for lets say
.551 = -log (#)
i know some properties of log lets say if i want to find 2^n = 6
i would do (log 6)/ (log 2)
but negatives are messed up
yes i know this is highschool but its been over 3 years for me since ive last done this |
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| Psionic |
0.551 = -log(x)
-0.551 = log(x)
10^(-0.551) = x
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| Nrg2Nfinit |
| quote: | Originally posted by Psionic
0.551 = -log(x)
-0.551 = log(x)
10^(-0.551) = x
? |
lol that denatley works.. maybe i should take high school math again :p |
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| Psionic |
| LOL glad I could help, I myself haven't taken high school math in awhile. |
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| THE_Chris |
| Bad memories of these bloody things :( |
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| AirPole |
| Truly unbelievable that I was once able to solve this kind of thing. I still can't believe it. |
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