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Simple Math? (pg. 4)
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| zoogla |
| quote: | Originally posted by leph555
its simpler after you get rid of some legs |
I suppose because the incision is occuring above the ankle, one could argue that a loss of leg is expected in that pictar. |
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| spc |
WE NEED CONFIRMATION OF THE CORRECT ANSWER
IF I AM WRONG I WILL NOT EVEN BOTHER TAKING THE CFA I IN JUNE AND /WRISTS :wtf: |
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| Silky Johnson |
| quote: | Originally posted by Aristronica
i mean the legs are obviously still on the train, pickled in jars. gypsies don't let body parts go that easy. |
:stongue: :stongue: |
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| zoogla |
| quote: | Originally posted by spc
I see you edited your initial post and got the same calculations as me... so I guess you are bringing me down with you in this mathematical event :sadgreen: |
lol no, we got it right silly!! But I win! ;) I also edited the post you quoted because I got the times wrong. FAIL! :tongue2 |
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| SimFox3 |
p = 4
d = 4 + 7p
b = 7d
c = 2 + 7b
T = 7c
T = 7(2+7b)
T = 7(2 + 7(7d))
T = 7(2 + 7(7(4+7p)))
T = 7(2 + 7(7(4+7(4))))
T = 10990
Do I win a prize? :tongue2 |
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| Frenchie |
| The same answer keeps coming up and yet each new person who writes it think they cracked it. |
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| SimFox3 |
Let a = b
Then a + a = b + a
2a = b + a
2a - 2b = b + a - 2b
2a - 2b = a - b
2(a - b) = (a - b)
2(a - b) = 1(a - b)
2 = 1 |
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| _Nut_ |
| quote: | Originally posted by Frenchie
The same answer keeps coming up and yet each new person who writes it think they cracked it. |
Also the thread starter posted the solution too... who'da thunk that? |
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| Erotic Buddha |
HEY GUYS I GOT THE ANSWER I GOT THE ANSWER I JUST CALCULATED IT!!
10990 |
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| Jake Benson |
| quote: | Originally posted by SimFox3
Let a = b
Then a + a = b + a
2a = b + a
2a - 2b = b + a - 2b
2a - 2b = a - b
2(a - b) = (a - b)
2(a - b) = 1(a - b)
2 = 1 |
FLAWED!
2(a-b) = 1(a-b); THEREFORE
2(0) = 1(0)
0 = 0
EXAMPLE and actual conclusion:
Let a = b. Let a = 4, therefore b = 4
a = b
4 = 4
Then a + a = b + a
4 + 4 = 4 + 4
2a = b + a
2(4) = 4 + 4
2a - 2b = b + a - 2b
2(4) - 2(4) = 4 + 4 - 2(4)
2a - 2b = a - b
2(4) - 2(4) = 4 - 4
2(a - b) = (a - b)
2(4 - 4) = (4 - 4)
2(a - b) = 1(a - b)
2(4 - 4) = 1(4 - 4)
2(0) = 1(0)
2(0) = 1 (0)
0 = 0
YOU HAVE BEEN MATHEMATICALLY BETCH SLAPPED! |
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| Boomer187 |
| i think I solved it, 10990? |
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| Pokit |
| quote: | Originally posted by SimFox3
Let a = b
Then a + a = b + a
2a = b + a
2a - 2b = b + a - 2b
2a - 2b = a - b
2(a - b) = (a - b)
2(a - b) = 1(a - b)
2 = 1 |
not true.
since a=b, then a-b=0.
in the second to last step you have to divide both sides by a-b (dividing by ZERO).
edit: damnit, didn't see jake benson's post >< |
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