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NEW - Any scientists/mathmaticians? Quick question (pg. 3)
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| Zild |
| It sounds right to me. You can express that answer in cells per ml^-1 which will be 7.5x10^6 cells/ml^-1. But it seems like you are doing it the right way and you have the right answer. |
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| Zild |
| quote: | Originally posted by KiNeTiC ENeRgY
Good deal. It's tough to get anywhere in science w/o a phd anymore, and the money is usually garbage to boot. |
Yeah if you're retarded and don't realize that you have huge ing claws and fangs and that if you work for yourself you will make at least 100,000/year to upwards of tens of millions once the heavy hitters come around trying to buy your company. |
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| NeoPhono |
x^-1 = 1/x
ml^-1 = 1/ml
It's another way of writing something (for example) as 5,000/ml (as in 5,000 units per ml). Instead you'd write 5,000 ml^-1. |
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| mames |
| quote: | Originally posted by NeoPhono
x^-1 = 1/x
ml^-1 = 1/ml
It's another way of writing something (for example) as 5,000/ml (as in 5,000 units per ml). Instead you'd write 5,000 ml^-1. |
This. Doing the calculations you get the number of cells per volume of culture, that is cells/ml = cells x ml-1 = 7500 ml-1 |
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| NeoPhono |
Here's an example of it being used (although it's still much more common to see x/ml than x ml-1).
http://www.tripdatabase.com/spider.html?itemid=630762
| quote: | | Antiemetic effect of ondansetron 0.2 mg mL-1 in PCA morphine solution. |
Which is the same as "0.2 mg/mL"
EDIT: This is probably a more fitting example;
http://www.natureprotocols.com/2008...spheres_fro.php
From the "Proceedure" section;
| quote: | | Plate the single-cell ES cell suspension in 50 ml fresh EB medium at a density of 105 cells ml-1 onto 15-cm bacterial dishes. |
There are more examples there as well... |
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| Zild |
| yeah ml^-1 is units per mil just like s^-1 = hz |
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| - T - |
| quote: | Originally posted by Azz3D
1/ml |
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| Jackson |
Ahh Still stuck on this bull.
Im just gonna write down all the info i have:
Ok the basic experiment is to work out the viability of a cuture of S. cerevisiae
We have already calculated the total count as 7.5x10^7 (or 75,000,000)
Now i'm calculating the Viable count (number of living cells).
I have calculated the average number of colonies in a 10^-4 dilution and a 10^-5 dilution.
In the 10^-4 dilution there were 165 colonies in agar.
So per ml I work this out to be 1.65x10^6 (correct?)
In the 10^-5 dilution there were 10 colonies in agar.
So per ml I work this out to be 1.0x10^6 (correct??)
The average of these two figures is 1.325x10^6 (or 1,325,000)
Percentage viability of a culture = viable cells divided by total cells x 100%
So 1.325x10^6 over 7.5x10^7 x100 = 1.77%
This seems very low to me, and i think i've missed a zero out somewhere beacause 17.7% would be more believable.
Any ideas???
Thanks everyone for this, its just I need to get past this to complete the rest of the work.
Cheers |
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| we_R_DNA |
| quote: | Originally posted by Jackson
I've got a serious mental block and cant work this out.
What does ml-1 equal? I am not too bad with scientific notation since we've just come onto it. But I can't work it out...would it be nanolitres? centilitres? |
technically 1*1 = 1 right
so 1 * ml = ml or 1ml
So you have (1ml)^-1 = (1)/(1ml)
and 1ml = 1*10^-3 L = .001L
so you have (1ml)^-1 = (1)/(1ml) = (1)/(.001L) |
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