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You don't get to delete**** threads Lascodi.. (pg. 9)
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XaNaX
maybe we could get all the alts from the COR recently to troll this thread, then it would be epic
KiNeTiC ENeRgY
quote:
Originally posted by Lascodi
isnt that just eta=W/Q=(1000/1500)J=0,67?


Nope. Not even close.

*edit*

Actually your Eq. is just backwards.
Frenchie
SO you admit you're a turd?
elFreak
quote:
Originally posted by Lascodi
no, its a turd battle


quoted for truth.
XaNaX
quote:
Originally posted by Lascodi
isnt that just eta=W/Q=(1000/1500)J=0,67?


wrong the answer is who ing cares
KiNeTiC ENeRgY
quote:
Originally posted by Lascodi
sorry eta
=w/q=(1500/1000)=1,5


It's 500J :( or 33%
XaNaX
now this is just getting painful to watch
XaNaX
lets try something more on your level maybe

2 + 2 = ?
KiNeTiC ENeRgY
quote:
Originally posted by Lascodi
-9, but you have to use navier-stokes to find it


Ok, I'll give u one last shot...This time it's multiple choice:


1) An ideal gas is quickly compressed in an insulated environment. During this process, the gas exchanges no energy
(or heat) with its surroundings. The process is thus an ___________ process.

a. isothermal
b. isometric
c. isobaric
d. adiabatic
zoogla
if this thread keeps going much long the whole intarweb will implode.

KiNeTiC ENeRgY
quote:
Originally posted by Lascodi
Diesel-cycle/process?


irrelevant.
KiNeTiC ENeRgY
quote:
Originally posted by Lascodi
Ah...misunderstood again...its adiabatic of course


We have a Weiner! :crazy: You so googled it didn't u
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