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x + y = x, solve for X
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| placebo |
x + y = x
solve for x
anyone?? |
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| hadi burpee |
x = y + x
x = x - y
y = 0
x is whatever you want |
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| placebo |
| quote: | Originally posted by hadi ******
x = y + x
x = x - y
y = 0 |
Wouldn't that be -y = 0? |
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| TranceGiant |
| x is any number, y must be 0. |
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| hadi burpee |
| quote: | Originally posted by placebo
Wouldn't that be -y = 0? |
there is no negative 0 |
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| Galapidate |
| Still if you multiply both sides by -1 or divide out by -1, it is still y=0. |
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| basd |
| quote: | Originally posted by placebo
Wouldn't that be -y = 0? |
Of course not.. Anything you pass to the other side of the equation mark is multiplied by -1. On the right side it says -y, so bringing it to the left side yields y. |
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| zarathustra |
| sqrt(x^2) = ? |
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| basd |
| quote: | Originally posted by zarathustra
sqrt(x^2) = ? |
:p
For the record: x or -x :) |
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| zarathustra |
| quote: | Originally posted by basd
:p
For the record: x or -x :) |
Be more specific. |
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| Jer |
| quote: | Originally posted by placebo
x + y = x
solve for x
anyone?? |
y = x - x
y = 0
Oops! I solved for y, not x! But since there's an x on both sides of the equation, it doesn't matter what x is, cause it'll amount to 0.
But!
If 0/x = 0, and x/x = 1, and x/0 is undefined(?), what is 0/0? (0,1,or undefined?) |
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| zarathustra |
x/0 -> inf for x!=0
x/0 -> undefined for x=0 |
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