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Something for your mind (pg. 3)
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zzleeper
Welll at firsthhs aie thouthg tath dizz culd be done in seevensteps,,,

8 0 0
3 5 0
3 2 3
6 2 0
6 0 2
1 5 2
1 4 3
4 4 0

bur ai wasent shure sou i niided two teshht it

souu i picked up theee bootelsss and theee wiennnn
and started puouring wine frommm oneee to otheerrr and soo onnnn..

thenn i finally rialized thatt i wass wrong.. ifff u have 8 litres off wine,, u shuldnt be thinkin about splittin dividin puourinng or somethink lige thatttt

washtt u shulddtthh dooo is ehhhh drink the goddamnetd wiiiineeeee
soooo i diddd ittt and was able toooo split theee wineeee inn 2 parts... one in mai stomachhh and miiii friendsss stomahhccc and anutheerr in thefloourr...

ehhh weeee nizeeee oneee qozmooooo... plizz make one of tekillla nexxt winee ehh timeee

:o :stongue:
TranceGiant
damn just as i finished i see ^^^^^post..anyway ill post my version...i think itdiffers in one step..donno
anyway:
3 5 0
3 2 3
6 2 0
6 0 2
1 5 2
1 4 3
4 4 0

edit: okay he had exactley da same solution..gotta be faster next time then
TranceGiant
kay, is this one possible? gimme the numbers!
a^n+b^n= c^n for n > 2 ;)
zzleeper
quote:
Originally posted by TranceGiant
kay, is this one possible? gimme the numbers!
a^n+b^n= c^n for n > 2 ;)


Can u have negative numbers...??




PS: This makes me remember a famous math. proof.
Cosmo
quote:
Originally posted by TranceGiant
kay, is this one possible? gimme the numbers!
a^n+b^n= c^n for n > 2 ;)


Yeah,yeah! Prove that and you'll be 1.000.000 $ richer! + plus Fild(?) Grant and respect of all mathematicians in the world :D ;)
As for just example (not proof):
a=b=c=0 :toothless
Cosmo
quote:
You have 12 steel balls. All of them look totally equil. But one of them is defect. It's either lighter, either heavier then the rest balls - no one knows!
We have scales, that can show only: left pan is heavier, right pan is heavier, their weight is equil.
You have to find defect ball and tell wether it's heavier/lighter IN 3 WEIGHING!!

Here's the answer:
1)Devide all balls into 3 groups - 4 balls in each - 1, 2 and 3
2)First weighing: we compare 1 Vs. 2 group - this weighing will tell wich group is lighter (if defect ball in third group solution is obvious)
3)Second weighing: on EACH scale's pan we put TWO balls from lighter group and also one ball form heavier group (3 balls Vs. 3 balls)
After weighing defect ball is either among two balls (from lighter group) on lighter pan or either in one ball (from heavier group) on heavier pan.
4)Last, third weighing - compare two light balls.
Metabeing
opppp some already postd answer...didnt see it
Metabeing
quote:
Originally posted by TranceGiant
kay, is this one possible? gimme the numbers!
a^n+b^n= c^n for n > 2 ;)



man thats fermats enigma...it was proven. Just cant remember how.
TranceGiant
fermats last theorem or whatever this was called, yeah tried to be jokin..hehe..not funny
as far as i know it was proven that there is NO solution..anyway the prove is said to be too complicated to understand..yeah
i had maths exam today by the way..what a mess :whip:
Cosmo
So, the "new" one :)
One half of the road car was moving with speed=12 km/h. Rest of the road with speed=4 km/h.
What is it's average speed?

zzleeper
Fermatīs last theorem was one of the last "big" theorems that lacked a mathemathical proof. A scientific from MIT?HARVARD? prooved it in 1992 i think.. the answer was like 200 pages long.. and it took him like 3 days straight to prove the answer in a "class" he did.


-- So about this one...
So, the "new" one
One half of the road car was moving with speed=12 km/h. Rest of the road with speed=4 km/h.
What is it's average speed?

Itīs not 8. I think it has to do with something called an armonic average (bad translation maybe).
Cosmo
Sides of the triangle ABC are equil= 18, 23 and 41 sm, while sides of the tri. DEF - 25, 33 & 58 sm. Which triangle area is bigger? ;)
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