|
any math people... (pg. 2)
|
View this Thread in Original format
| Trancealot |
| ok thanks for the replies. Now I will look at what you got and try to work at it again |
|
|
| Trancealot |
| quote: | Originally posted by jennypie
Isn't that like, grade 9/10 math?? |
9/10 grade math is x^2 only
x^3 is a whole new ball game
that site is fine and got my answers but if you attempted it yourself as you can see it just does the big ol' ax^3+bx^2+cx+d = 0 formula for the three unknowns. I want to stay away from that ugly thing because I know there is a way to do it otherwise.
| quote: | Originally posted by Cloudburst
If x=a is a solution, do Polynomial Long Division :
Ax^3 + Bx^2 + Cx + D / (x-a)
You will get Ax^2 + Bx + C = 0
solve it with
 |
this might be fine but I'll need some more time to figure this. Later tonight I hope |
|
|
| Ang ' ela_ie |
| quote: | Originally posted by Trancealot
9/10 grade math is x^2 only
x^3 is a whole new ball game |
Yeah, polynomial division... scary stuff! :rolleyes: |
|
|
| kadomony |
like this?
 |
|
|
| Trancealot |
| quote: | Originally posted by kadomony
like this?
|
hmm thats something (cardano method) I see too many methods but this looks fine. I wonder if anyone could break this up the old fashion way if possible but if not then I will stick with this.
PS.what program or website did you use. :) |
|
|
| Krypton |
This is as far as I got in factoring...
-x^2(x-16)-(73x-99)
73 is a prime number. I can't get this down any further without using some crazy method and making it a decimal fraction. Use the Cardano Vieta formula. |
|
|
| _Nut_ |
| quote: | Originally posted by Ang ' ela_ie
Yeah, polynomial division... scary stuff! :rolleyes: |
But the internets stops all scary...not figuring it out on your own! |
|
|
| Silky Johnson |
| quote: | Originally posted by Trancealot
9/10 grade math is x^2 only
x^3 is a whole new ball game
|
Uh, maybe if you were in the retard class. |
|
|
| Zild |
Does the problem instruct you to factor the equation? Or is it up to you to figure out which method?
If you're supposed to factor then you copied the problem incorrectly or there is a typo somewhere because you can't factor that one. |
|
|
| kadomony |
| quote: | Originally posted by Trancealot
hmm thats something (cardano method) I see too many methods but this looks fine. I wonder if anyone could break this up the old fashion way if possible but if not then I will stick with this.
PS.what program or website did you use. :) |
http://www.equationwizard.com/ :) |
|
|
| Rose |
| oh that . math. PM sunsnail hes really good at math. |
|
|
| Leon |
| i'm bad at math and I have 4 courses to go :( |
|
|
|
|
