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An updated Monty Show paradox for all you COR brainiacs (pg. 4)
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| Psy-T |
| quote: | Originally posted by mezzir
ITS NOT INFINITY
THEY'RE LIMITED TO INTEGERS BETWEEN 1 AND THE BIGGER OF THE 2 NUMBERS XANDER WRITES
SO IT COULD BE A HUGE SCOPE, BUT ITS FINITE |
stop yelling at me! :mad: :p |
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| mezzir |
| quote: | Originally posted by Psy-T
stop yelling at me! :mad: :p |
I'M BEING FESTIVE! |
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| Akridrot |
That's the exact pdf too. Good job googling answers, freak. :mad:
Sorry about misleading y'all though. |
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| Psy-T |
| i still contend there's something wrong with the question :p |
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| ZeJayMan |
Brothers and sisters have I none,
but this man's father's son is my father's son. |
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| Akridrot |
| quote: | Originally posted by ZeJayMan
Brothers and sisters have I none,
but this man's father's son is my father's son. |
You |
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| Akridrot |
How do you cut a cake into 8 pieces with 3 slices?
(I know the answer) |
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| Psy-T |
| quote: | Originally posted by ZeJayMan
Brothers and sisters have I none,
but this man's father's son is my father's son. |
you're just being convulted there, that man is obviously you :p
3 points for me in this therad so far, right? :D
edit, damn akridrot *mumbles* |
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| Psy-T |
| quote: | Originally posted by Akridrot
How do you cut a cake into 8 pieces with 3 slices?
(I know the answer) |
when cake=
/-\
|0|
\-/
first slice \
second slice /
then flip it to the side and ---- |
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| Akridrot |
| quote: | Originally posted by Psy-T
when cake=
/-\
|0|
\-/
first slice \
second slice /
then flip it to the side and ---- |
You think you're soooooooooooooooooooo clever. But you are right.
*I'm going to change words to make it ungoogleable*
I want to put 14 packets of Nutra-Sweet into 3 cups of tea. How would I put an odd number of Nutra-Sweets in each cup? :D |
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| ZeJayMan |
| zero in the first one, 7 in the other two>? |
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| pkcRAISTLIN |
| quote: | Originally posted by Psy-T
you're the one who thinks that past event affect the future event by increasing your choices' probability from 2/5 to 2/3; the elimination of two doors does not increase the probability of your initial choices in being right, however, it does inherently tell us that those two doors have a zero probability of holding the car, and hence the last door has a probability of 3/5 of holding the car. |
im not understanding the logic youve used, with the 3/5 here. why arent the odds changed to each door being 1/3 chance? if you had five doors, and five contestants got to choose a door each, the chances of a correct guess will increase that corresponding amount, but no unopened door is ever going to have more of a chance than any other unopened door.
after the host has opened the two empty doors, the probabilities change to 1/3 for each door, given that your two initial selections could already have the car covered. |
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