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any math people...
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| Trancealot |
I have this equation: -x^3+16x^2-73x+99 = 0
I want to know how to factor this?
I have programs that solve for the roots:
x1:9.28799213896
x2:2.578933385691
x3:4.133074475349
but my goal is to show how I obtained them. I guess in fractional form
I know you must remove the negative sign in front so it becomes:
x^3-16x^2+73x-99=0
but then the rest I can't see how to break it apart.
Thanks if anyone can get me in the right direction... |
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| infinity HiGH |
| umm since the equation = 0, all u do is flip everything to the other side of the = and voila, the + becomes - and vice versa. I dont see what the problem here is |
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| Silky Johnson |
| Isn't that like, grade 9/10 math?? |
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| infinity HiGH |
| maybe he IS in grade 9/10?:rolleyes: |
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| Silky Johnson |
| off, Pete. :rolleyes: |
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| Meat187 |
You made a mistake copying the equation. I should say:
-x^3 + 16*x^2 - 73*x + 90 = 0 |
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| Orbital32 |
DON'T DIVIDE BY ZERO!!!
you will destroy the world. |
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| wienerschnitzel |
| no. there is an elephant in the way |
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| Lira |
| quote: | Originally posted by Trancealot
I can't see how to break it apart. |
Before: X
After: > < |
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| Cloudburst |
If x=a is a solution, do Polynomial Long Division :
Ax^3 + Bx^2 + Cx + D / (x-a)
You will get Ax^2 + Bx + C = 0
solve it with
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